ChemistryCore22 min read

Redox & Electrolysis

Electron transfer, and using electricity to split compounds apart

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Practise the full question bank:

01

Redox is electron transfer

A redox reaction is any reaction where electrons move from one species to another. Two things always happen together: one substance loses electrons and the other gains them. The mnemonic settles it — OIL RIG: Oxidation Is Loss, Reduction Is Gain (of electrons).

The substance that gives electrons away is oxidised; the one that takes them is reduced. An oxidising agent accepts electrons (so it is itself reduced); a reducing agent donates them. In the older sense, oxidation can also mean gaining oxygen or losing hydrogen — the electron definition is the one that always works.

02

Electrolysis: forcing a reaction with electricity

Electrolysis uses an electric current to split an ionic compound into its elements. It only works when the ions are free to move — so the compound must be molten or dissolved; a solid ionic compound will not electrolyse because its ions are locked in the lattice.

Two electrodes dip in. The cathode is negative: positive ions (cations) are attracted there and gain electrons — reduction. The anode is positive: negative ions (anions) go there and lose electrons — oxidation. So reduction always happens at the cathode, oxidation at the anode.

Two anchors that never change

Cathode = negative = reduction (cations gain electrons). Anode = positive = oxidation (anions lose electrons). Memorise this pair and every electrolysis question becomes "which ion goes where".

03

Molten vs aqueous

Electrolysing a molten compound is simple: the metal forms at the cathode, the non-metal at the anode. Molten lead(II) bromide gives lead at the cathode and brown bromine vapour at the anode.

A solution is trickier because water also provides H⁺ and OH⁻. At the cathode you get the metal only if it is less reactive than hydrogen; otherwise hydrogen bubbles off. At the anode you get a halogen if a halide is present; otherwise oxygen. So electrolysing brine (concentrated NaCl solution) gives hydrogen, chlorine and sodium hydroxide — the basis of a whole industry.

04

Why it matters

Electrolysis extracts the most reactive metals (aluminium from molten aluminium oxide — nothing else can pull the oxygen off), electroplates objects with a thin metal layer (the object is the cathode, the plating metal the anode), and purifies copper for wiring. It is expensive because it needs so much electricity, which is exactly why recycling aluminium is worth it.

05

A worked example

Worked example

Molten lead(II) bromide is electrolysed. What forms at each electrode, and which process is which?

  1. The ions free to move are Pb²⁺ and Br⁻.Molten, so the lattice has broken and ions can migrate.
  2. Pb²⁺ goes to the cathode and gains electrons → lead metal. This is reduction.Cathode is negative; cations gain electrons (OIL RIG: gain = reduction).
  3. Br⁻ goes to the anode and loses electrons → bromine. This is oxidation.Anode is positive; anions lose electrons (loss = oxidation).

Lead at the cathode (reduction), bromine at the anode (oxidation).

06

Oxidation numbers — keeping score

An oxidation number is a signed value that tracks how many electrons an atom has gained or lost. A few rules cover most cases: uncombined elements are 0; a simple ion equals its charge; oxygen is usually −2 and hydrogen +1; and the numbers in a compound add up to zero (or to the ion's charge).

They make redox easy to spot: an atom whose oxidation number rises has been oxidised, and one whose number falls has been reduced — even in reactions where no obvious electron transfer is written.

07

Useful electrolysis: brine, plating and purifying copper

Electrolysing concentrated sodium chloride solution (brine) is a major industry: it gives hydrogen at the cathode, chlorine at the anode, and sodium hydroxide left in solution — three valuable products used for margarine, bleach and soap.

Electroplating coats a cheap object with a thin layer of an expensive metal by making the object the cathode in a solution of that metal's ions. And impure copper is purified by electrolysis: the impure copper is the anode and dissolves, while pure copper deposits on the cathode, leaving impurities behind as sludge.

Choosing the products in solution

At the cathode, the less reactive of hydrogen and the metal is produced (so hydrogen forms unless the metal is below it, like copper). At the anode, a halide gives the halogen; otherwise oxygen is released from water.

Practice questions

6 questions · 22 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 9 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Define oxidation and reduction in terms of electrons.
Model answer

Oxidation is loss of electrons; reduction is gain of electrons (OIL RIG).

Examiner tip. Oxidation Is Loss, Reduction Is Gain — of electrons.

SQ2[2 marks]
State what is meant by electrolysis.
Model answer

The breakdown (decomposition) of an ionic compound, when molten or in aqueous solution, by the passage of an electric current.

Examiner tip. Electrolysis needs a liquid with mobile ions (molten or aqueous).

SQ3[3 marks]
During the electrolysis of molten lead(II) bromide, write the electrode reactions and name the products.
Model answer

Cathode (−): Pb²⁺ + 2e⁻ → Pb (lead metal). Anode (+): 2Br⁻ → Br₂ + 2e⁻ (bromine gas).

Examiner tip. Positive ions go to the cathode and gain electrons; negative ions go to the anode and lose electrons.

SQ4[2 marks]
Deduce the oxidation number of manganese in the permanganate ion, MnO₄⁻.
Model answer

Oxygen is −2, so 4 × (−2) = −8. The whole ion has a charge of −1, so Mn + (−8) = −1, giving Mn = +7.

Examiner tip. Set the sum of oxidation numbers equal to the overall ion charge and solve.

Long questions

2 · 13 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[7 marks]
Molten aluminium oxide is electrolysed to extract aluminium.
  1. Explain why the aluminium oxide must be molten. [2]
  2. Write the half-equation for the reaction at the cathode. [2]
  3. State the product at the anode and explain why the carbon anodes must be replaced regularly. [3]
Mark scheme
  1. Melting frees the ions[1]
  2. so they can move to the electrodes and carry the current[1]
  3. Al³⁺ + 3e⁻ → Al[1]
  4. balanced with electrons[1]
  5. Oxygen is produced at the anode[1]
  6. The hot oxygen reacts with the carbon anodes forming carbon dioxide[1]
  7. so the anodes burn away and must be replaced[1]

Molten = mobile ions to carry current; cathode Al³⁺ + 3e⁻ → Al; anode makes O₂, which burns the carbon anodes to CO₂ so they wear away.

Examiner tip. Reduction (gain of e⁻) happens at the cathode; oxidation (loss of e⁻) at the anode.

LQ2[6 marks]
Impure copper is purified by electrolysis using copper electrodes in copper(II) sulfate solution.
  1. State which electrode is made of impure copper, and the half-equation there. [2]
  2. State what forms at the other electrode, with its half-equation. [2]
  3. Explain what happens to the impurities. [2]
Mark scheme
  1. The anode (positive electrode) is the impure copper[1]
  2. Cu → Cu²⁺ + 2e⁻ (copper dissolves)[1]
  3. Pure copper deposits on the cathode[1]
  4. Cu²⁺ + 2e⁻ → Cu[1]
  5. Impurities do not dissolve / are not deposited[1]
  6. they collect below the anode as anode sludge[1]

Anode = impure copper (Cu → Cu²⁺ + 2e⁻); cathode gains pure copper (Cu²⁺ + 2e⁻ → Cu); impurities drop as anode sludge.

Examiner tip. In copper purification the anode dissolves and the cathode grows purer.