ChemistryCore20 min read

Energy Changes

Exothermic and endothermic reactions, and where the energy comes from

This topic appears in:

Practise the full question bank:

01

Reactions take in or give out energy

Every reaction involves an energy change, almost always as heat. An exothermic reaction releases energy to the surroundings, so the temperature rises — combustion, respiration, neutralisation, and most reactions of metals. An endothermic reaction takes in energy, so the surroundings cool — thermal decomposition, photosynthesis, and dissolving some salts.

A quick lab test is just a thermometer: temperature up means exothermic, temperature down means endothermic.

02

Energy profiles

An energy profile plots the energy of the reactants and products. In an exothermic reaction the products sit lower than the reactants — energy was released — so the overall energy change, ΔH, is negative. In an endothermic reaction the products sit higher and ΔH is positive.

On both profiles there is a hump between reactants and products: the activation energy, the barrier every reaction must climb before it can proceed. A catalyst lowers that hump without changing the reactants or products.

03

Where the energy actually comes from: bonds

The energy change is bookkeeping on bonds. Breaking bonds takes energy in (endothermic); making bonds gives energy out (exothermic). Every reaction does both — old bonds break, new ones form — and the net result is the difference.

If making the new bonds releases more than breaking the old ones absorbed, the reaction is exothermic overall. If breaking costs more than making returns, it is endothermic.

ΔH = (energy to break bonds) − (energy released making bonds)negative ΔH = exothermic · positive ΔH = endothermic
04

A worked example

Worked example

Burning methane is strongly exothermic and gets a flame going. Using bonds, explain why it releases energy, and state the sign of ΔH.

  1. Breaking the C–H bonds in methane and the O=O bonds in oxygen takes energy in.Bond breaking is always endothermic.
  2. Forming the C=O bonds in CO₂ and O–H bonds in H₂O releases energy.Bond making is always exothermic.
  3. The new bonds release more energy than the old bonds absorbed, so there is a net release.Overall energy out > energy in.
  4. The products are lower in energy than the reactants, so ΔH is negative.Exothermic reactions have a negative ΔH.

Making the product bonds releases more than breaking the reactant bonds absorbs, so energy is given out overall — exothermic, ΔH negative.

05

Measuring energy changes — calorimetry

You cannot see energy, but you can measure the temperature change it causes. In calorimetry a reaction (say burning a fuel, or a neutralisation) heats a known mass of water, and the heat transferred is found from q = mcΔT. Dividing by the moles reacted gives the energy change per mole.

Real measurements always fall short of data-book values because heat escapes to the surroundings and combustion is often incomplete — a good reason to insulate the apparatus and shield it from draughts.

q = m c ΔTq = heat energy (J) · m = mass of water heated (g) · c = 4.2 J/g/°C · ΔT = temperature change
06

Types of enthalpy change and Hess's law (A Level)

Chemists name specific energy changes: the enthalpy of combustion (burning one mole in oxygen), of neutralisation (acid + alkali making one mole of water) and of formation (making one mole of a compound from its elements). All are quoted per mole under standard conditions.

Hess's law says the total enthalpy change of a reaction is the same whatever route is taken, because energy is conserved. That lets you calculate an enthalpy change you cannot measure directly by adding up the steps of an alternative route through an energy cycle.

Practice questions

6 questions · 21 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 9 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Define an exothermic reaction and give one example.
Model answer

A reaction that transfers energy to the surroundings (temperature of surroundings rises), e.g. combustion / neutralisation.

Examiner tip. Exothermic = energy out (surroundings warm); endothermic = energy in (surroundings cool).

SQ2[2 marks]
In terms of bond breaking and bond making, explain why a reaction is exothermic.
Model answer

Bond breaking absorbs energy and bond making releases energy; in an exothermic reaction more energy is released making bonds than is absorbed breaking them.

Examiner tip. Energy released (bonds made) − energy absorbed (bonds broken) = overall energy change.

SQ3[3 marks]
Sketch and label an energy level diagram for an exothermic reaction, marking the activation energy and the enthalpy change (ΔH).
Model answer

Reactants at a higher energy than products; a 'hump' above the reactants marks the activation energy; ΔH is the (negative) drop from reactants to products.

Examiner tip. For exothermic, products sit BELOW reactants, so ΔH is negative.

SQ4[2 marks]
Burning a fuel raises the temperature of 200 g of water by 25 °C. Calculate the heat energy transferred to the water. (c = 4.2 J/g/°C)
Model answer

q = mcΔT = 200 × 4.2 × 25 = 21 000 J = 21 kJ.

Examiner tip. Use the mass of the water; multiply m, c and ΔT, then convert J to kJ (÷1000).

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
Hydrogen burns in oxygen: 2H₂ + O₂ → 2H₂O. Bond energies (kJ/mol): H–H = 436, O=O = 498, O–H = 464.
  1. Calculate the total energy absorbed to break the bonds in the reactants. [2]
  2. Calculate the total energy released when the bonds in the products form. [2]
  3. Calculate ΔH and state whether the reaction is exothermic or endothermic. [2]
Mark scheme
  1. Bonds broken = 2(H–H) + 1(O=O) = 2(436) + 498[1]
  2. = 872 + 498 = 1370 kJ[1]
  3. Bonds made = 4 O–H = 4 × 464[1]
  4. = 1856 kJ[1]
  5. ΔH = energy in − energy out = 1370 − 1856 = −486 kJ/mol[1]
  6. Negative ΔH, so the reaction is exothermic[1]

Broken = 1370 kJ; made = 1856 kJ; ΔH = −486 kJ/mol → exothermic.

Examiner tip. ΔH = (bonds broken) − (bonds made). Note 2H₂O contains 4 O–H bonds.

LQ2[6 marks]
0.32 g of methanol is burned and heats 100 g of water by 24 °C. (c of water = 4.2 J/g/°C; Mr methanol = 32)
  1. Calculate the heat energy released to the water. [2]
  2. Calculate the enthalpy of combustion of methanol in kJ/mol. [3]
  3. Suggest one reason the value is less negative than the data-book value. [1]
Mark scheme
  1. q = mcΔT = 100 × 4.2 × 24[1]
  2. = 10 080 J = 10.08 kJ[1]
  3. moles methanol = 0.32 ÷ 32 = 0.010 mol[1]
  4. ΔH = 10.08 ÷ 0.010 = 1008 kJ/mol (magnitude)[1]
  5. ΔH ≈ −1010 kJ/mol (exothermic, so negative)[1]
  6. Heat lost to the surroundings / incomplete combustion / evaporation[1]

q = 10.08 kJ; ΔH ≈ −1010 kJ/mol; less negative than the true value because heat escapes / combustion is incomplete.

Examiner tip. Combustion is exothermic so ΔH is negative; heat loss always makes the measured magnitude smaller.