ChemistryCore22 min read

Atomic Structure

Shells, configuration and periodic trends

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Practise the full question bank:

01

Three particles, two jobs

Protons define what element you have. Six protons is carbon, and nothing else can be carbon. Neutrons change the mass but not the chemistry — that is what isotopes are. Electrons do all the chemistry.

Every reaction you will ever study is electrons rearranging. The nucleus sits there unchanged unless you are doing nuclear physics.

ParticleChargeRelative massLocation
Proton+11Nucleus
Neutron01Nucleus
Electron−11/1836Shells around the nucleus
02

Electrons live in shells

Electrons cannot sit anywhere they like. They occupy discrete energy levels — shells — filling from the inside out. Shell capacities follow 2n²: 2, 8, 18, 32.

Only the outermost shell — the valence shell — takes part in bonding. This single fact explains the entire shape of the periodic table: elements in the same group have the same number of valence electrons, so they behave the same way.

Slide from Li (3) to Na (11) to K (19). All three have exactly one valence electron — that is why they are all violently reactive alkali metals, and why they sit in the same column.

03

Atomic radius shrinks across a period. Counter-intuitive, but correct: you are adding protons and electrons to the same shell, so the growing nuclear charge pulls that shell in tighter. Going down a group you add a whole new shell, so atoms get bigger.

Ionisation energy — the energy to remove the outermost electron — rises across a period (held more tightly) and falls down a group (further from the nucleus and shielded by inner shells).

Electronegativity — the pull on shared electrons — follows the same pattern, peaking at fluorine.

Switch between the three properties and watch the heat map flip direction. Radius brightens toward the bottom-left; electronegativity and ionisation energy brighten toward the top-right.

The noble gases explain everything else

Group 18 has a full outer shell, which is why they barely react. Every other element's chemistry is essentially an attempt to reach that same configuration — by losing electrons, gaining them, or sharing them. That is the whole of bonding in one sentence.

05

Isotopes and relative atomic mass

Not every atom of an element is identical. Isotopes are atoms of the same element — the same number of protons — with different numbers of neutrons, and so different mass numbers. Chlorine, for example, exists as chlorine-35 and chlorine-37. Because they have the same number of electrons arranged in the same way, isotopes are chemically identical; only their masses (and physical properties that depend on mass, like density) differ.

Since a real sample is a mixture of isotopes, the mass we quote for an element is a weighted average called the relative atomic mass (Ar) — the average mass of its atoms compared with 1/12 of the mass of a carbon-12 atom. The weighting is by how abundant each isotope is.

Aᵣ = Σ(isotope mass × % abundance) ÷ 100multiply each isotope's mass by its percentage, add them, divide by 100
06

Sub-shells and orbitals (A Level)

The simple shells (2, 8, 8 …) are really made of sub-shells labelled s, p, d and f, which hold up to 2, 6, 10 and 14 electrons respectively. Each sub-shell is divided into orbitals, regions that each hold at most two electrons spinning in opposite directions.

Sub-shells fill in order of increasing energy, which is why 4s fills before 3d: 1s 2s 2p 3s 3p 4s 3d 4p … We write the arrangement as an electron configuration, for example sodium is 1s² 2s² 2p⁶ 3s¹. The outer electrons this notation reveals are exactly the ones that decide an element's chemistry.

Sub-shellOrbitalsMax electrons
s12
p36
d510
f714
07

Ionisation energy (A Level)

The first ionisation energy is the energy needed to remove one electron from each atom in a mole of gaseous atoms. Removing successive electrons needs steadily more energy, because each electron is pulled from an increasingly positive ion. The big jumps in successive ionisation energies are strong evidence for shells: a sudden leap means you have started removing electrons from a shell closer to the nucleus.

Across a period, first ionisation energy generally rises (more nuclear charge, similar shielding, so electrons are held tighter); down a group it falls (the outer electron is further out and more shielded, so easier to remove). These are the same forces that drive reactivity.

Ionisation energies map the shells

Plot the successive ionisation energies of an element and the jumps reveal its electron arrangement — e.g. for sodium a large jump after the 1st electron shows a lone outer electron (2,8,1).

08

A worked example

Worked example

Chlorine is 75% chlorine-35 and 25% chlorine-37. Calculate its relative atomic mass, and write the full electron configuration of a chlorine atom (17 electrons).

  1. Aᵣ = (35 × 75 + 37 × 25) ÷ 100Relative atomic mass is the abundance-weighted mean of the isotope masses.
  2. = (2625 + 925) ÷ 100 = 3550 ÷ 100 = 35.5Add the weighted masses and divide by 100.
  3. Fill sub-shells in energy order for 17 electrons: 1s² 2s² 2p⁶ 3s² 3p⁵2 + 2 + 6 + 2 + 5 = 17 electrons.
  4. So chlorine has 7 outer-shell electrons and readily gains one to form Cl⁻.Seven outer electrons explain its Group VII chemistry.

Aᵣ = 35.5; electron configuration 1s² 2s² 2p⁶ 3s² 3p⁵ (7 outer electrons).

Practice questions

6 questions · 22 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 10 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State the relative charge and relative mass of a proton, a neutron and an electron.
Model answer

Proton: charge +1, mass 1. Neutron: charge 0, mass 1. Electron: charge −1, mass negligible (about 1/1840).

Examiner tip. The nucleus (protons + neutrons) holds almost all the mass; the electron's mass is treated as ~0.

SQ2[2 marks]
Define the term isotopes.
Model answer

Atoms of the same element (same number of protons / same proton number) that have different numbers of neutrons, and so different mass numbers.

Examiner tip. Same protons = same element and same chemistry; different neutrons = different mass.

SQ3[3 marks]
An atom is represented as ³⁵₁₇Cl. State its number of protons, neutrons and electrons.
Model answer

Protons = 17, electrons = 17 (neutral atom), neutrons = 35 − 17 = 18.

Examiner tip. Bottom number = protons (= electrons if neutral); top number − bottom number = neutrons.

SQ4[3 marks]
Boron has two isotopes: boron-10 (20%) and boron-11 (80%). Calculate its relative atomic mass.
Model answer

Aᵣ = (10 × 20 + 11 × 80) ÷ 100 = (200 + 880) ÷ 100 = 1080 ÷ 100 = 10.8.

Examiner tip. Weight each isotope mass by its percentage abundance, add, divide by 100.

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
Chlorine exists as two isotopes, chlorine-35 and chlorine-37.
  1. Explain why the two isotopes have identical chemical properties. [2]
  2. A sample is 75% chlorine-35 and 25% chlorine-37. Calculate the relative atomic mass of chlorine. [2]
  3. State how many electrons chlorine has in its outer shell, and hence the charge on a chloride ion. [2]
Mark scheme
  1. Both isotopes have the same number of electrons / the same electronic configuration (2,8,7)[1]
  2. Chemical properties depend on the (outer) electrons, so they react identically[1]
  3. Ar = (35 × 75 + 37 × 25) ÷ 100sets up weighted mean[1]
  4. Ar = (2625 + 925)/100 = 35.5[1]
  5. 7 electrons in the outer shell[1]
  6. Gains 1 electron, so the chloride ion is Cl⁻ (charge −1)[1]

Same electron arrangement → identical chemistry; Ar = 35.5; 7 outer electrons, so Cl⁻.

Examiner tip. Relative atomic mass is a weighted average — multiply each isotope's mass by its percentage, add, divide by 100.

LQ2[6 marks]
This question is about the electronic structure of calcium (proton number 20).
  1. Write the full electron configuration of a calcium atom. [2]
  2. Write the electron configuration of a Ca²⁺ ion. [1]
  3. The successive ionisation energies of calcium show a large jump after the second electron is removed. Explain what this tells you. [3]
Mark scheme
  1. 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²[1]
  2. electron count totals 20[1]
  3. Ca²⁺: 1s² 2s² 2p⁶ 3s² 3p⁶ (loses the two 4s electrons)[1]
  4. The first two electrons are removed from the outer 4s sub-shell[1]
  5. The third is removed from the 3p, a shell closer to the nucleus[1]
  6. which is held much more strongly, so far more energy is needed — showing two electrons in the outer shell[1]

Ca = 1s²2s²2p⁶3s²3p⁶4s²; Ca²⁺ = 1s²2s²2p⁶3s²3p⁶; the jump after 2 electrons shows only two electrons in the outer shell.

Examiner tip. A big jump appears when removal moves to a shell nearer the nucleus.