ChemistryCore22 min read

The Periodic Table

Groups, periods, and the trends that let you predict a reaction

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Practise the full question bank:

01

The arrangement is not arbitrary

Elements are laid out in order of atomic number, but the genius of the table is the wrapping: each row (a period) fills one more electron shell, and each column (a group) collects elements with the same number of outer-shell electrons. Because chemistry is decided by outer electrons, a group is a family that behaves alike.

Metals sit on the left and centre, non-metals on the right, with a staircase of semi-metals between. The group number (for the main groups) tells you the valence electrons directly — group 1 has one, group 7 has seven.

Switch between the properties and watch the pattern: metals to the left, reactivity and size building toward the bottom-left for metals and the top-right for non-metals.

02

Group 1 — the alkali metals

Lithium, sodium, potassium: one outer electron they lose easily, so they are very reactive metals, stored under oil and forming +1 ions. React with water to give a hydroxide and hydrogen: 2Na + 2H₂O → 2NaOH + H₂.

The key trend: reactivity increases down the group. Lower down, the outer electron is further from the nucleus and more shielded, so it is lost more easily — potassium reacts far more violently than lithium.

03

Group 7 — the halogens

Fluorine, chlorine, bromine, iodine: seven outer electrons, needing just one more, so they are reactive non-metals forming −1 ions. They exist as diatomic molecules (Cl₂, Br₂).

Their trend runs the opposite way: reactivity decreases down the group, because gaining an electron gets harder as the outer shell sits further out. This gives displacement: a more reactive halogen pushes a less reactive one out of its salt — chlorine displaces bromine from potassium bromide.

Metals and non-metals trend in opposite directions

Metals get MORE reactive down a group (easier to lose an electron); non-metals get LESS reactive down a group (harder to gain one). The same cause — the outer shell moving away from the nucleus — helps a metal and hinders a non-metal.

04

Group 0 and the transition metals

Group 0 — the noble gases have a full outer shell, so they are unreactive (inert) and exist as single atoms. That stability is why they are used where you need something that will not react: argon in light bulbs, helium in balloons.

The transition metals in the centre are the "typical metals" — hard, dense, high melting points — but with extras: they form ions of more than one charge (Fe²⁺ and Fe³⁺), their compounds are often coloured, and many act as catalysts (iron in the Haber process).

05

A worked example

Worked example

Predict: (a) is potassium more or less reactive than sodium? (b) will chlorine displace iodine from potassium iodide?

  1. (a) Both are group 1 metals; potassium is further down, so its outer electron is lost more easily.Group 1 reactivity increases down the group.
  2. Potassium is MORE reactive than sodium.Further from the nucleus and more shielded → electron lost more readily.
  3. (b) Chlorine is higher in group 7 than iodine, so it is the more reactive halogen.Group 7 reactivity decreases down the group.
  4. Yes — chlorine displaces iodine: Cl₂ + 2KI → 2KCl + I₂ (the solution darkens as iodine forms).A more reactive halogen displaces a less reactive one from its salt.

(a) Potassium is more reactive; (b) yes, chlorine displaces iodine, forming potassium chloride and iodine.

06

Why the pattern repeats

The periodic table works because chemistry is decided by outer-shell electrons. Each new period starts a new shell, and across the period that shell fills up — so the same outer arrangements recur, and with them the same kinds of chemistry. The group number equals the number of outer electrons, and the period number equals the number of occupied shells.

That single idea explains everything else on the table: why Group 1 metals all react the same way, why Group 0 is inert, and why reactivity trends run the way they do.

07

Move across Period 3 (Na → Ar) and clear trends appear. Atomic radius decreases: the nuclear charge rises while electrons enter the same shell, pulling everything in tighter. First ionisation energy generally rises for the same reason, with small dips where a new sub-shell or a paired orbital begins.

Melting point rises to a peak at silicon then collapses: Na, Mg and Al are metallic (rising with more delocalised electrons), silicon is a giant covalent structure (very high), while P₄, S₈, Cl₂ and Ar are simple molecular or atomic with only weak forces (very low).

Element (Period 3)Structure / bondingMelting point trend
Na, Mg, Algiant metallicrises (more delocalised electrons)
Sigiant covalentvery high (peak)
P, S, Cl, Arsimple molecular / atomiclow (weak van der Waals forces)
08

Another worked example

Worked example

Explain why the atomic radius of the elements decreases across Period 3 from sodium to chlorine.

  1. Across the period, the number of protons in the nucleus increases.Each element has one more proton than the last.
  2. The extra electrons are added to the same outer shell.The shell number does not change across a period.
  3. So the shielding stays roughly the same while the nuclear charge rises.Same inner shells, more nuclear pull.
  4. The greater nuclear attraction pulls the outer shell in closer, so the atomic radius decreases.Stronger pull with similar shielding contracts the atom.

Increasing nuclear charge with almost constant shielding pulls the outer electrons in more strongly, so the atoms get smaller across the period.

Practice questions

6 questions · 21 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 9 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State how the elements are arranged in the modern Periodic Table.
Model answer

In order of increasing proton (atomic) number, arranged in periods (rows) and groups (columns) of similar properties.

Examiner tip. Group number = number of outer-shell electrons; period number = number of occupied shells.

SQ2[2 marks]
Describe the trend in reactivity down Group I and explain it.
Model answer

Reactivity increases down Group I because the outer electron is further from the nucleus and more easily lost.

Examiner tip. Group I metals react by LOSING one electron; easier loss = more reactive.

SQ3[3 marks]
Explain why the elements in Group VII show similar chemical properties but Group 0 (noble gases) are unreactive.
Model answer

Group VII atoms all have 7 outer electrons, so they react similarly (gaining/sharing one electron). Noble gases have a full outer shell, so they have no tendency to gain, lose or share electrons and are unreactive.

Examiner tip. Similar chemistry = same number of outer electrons; a full outer shell = stability = unreactivity.

SQ4[2 marks]
State and explain the trend in the reactivity of the Group 1 metals down the group.
Model answer

Reactivity increases down the group because the outer electron is further from the nucleus and more shielded, so it is lost more easily.

Examiner tip. Group 1 metals react by losing their single outer electron — easier loss means greater reactivity.

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
Chlorine, bromine and iodine are Group VII elements.
  1. Describe the trend in reactivity down Group VII and explain it. [3]
  2. Predict what happens when chlorine is added to a solution of potassium bromide, and write an equation. [3]
Mark scheme
  1. Reactivity decreases down the group[1]
  2. The outer shell is further from the nucleus / more shielded[1]
  3. So it is harder to attract/gain an electron[1]
  4. Chlorine is more reactive than bromine, so it displaces bromine[1]
  5. The solution turns orange (bromine formed)[1]
  6. Cl₂ + 2KBr → 2KCl + Br₂[1]

Reactivity falls down the group (outer shell further/shielded, harder to gain e⁻); chlorine displaces bromine: Cl₂ + 2KBr → 2KCl + Br₂.

Examiner tip. A more reactive halogen displaces a less reactive one from its salt — a displacement reaction.

LQ2[6 marks]
This question is about trends in Period 3 (Na to Ar).
  1. Describe how melting point changes across Period 3 and explain the value for silicon. [3]
  2. State the trend in first ionisation energy across the period and explain it. [3]
Mark scheme
  1. Melting point rises from Na to a peak at Si, then falls sharply to Ar[1]
  2. Silicon is a giant covalent (macromolecular) structure[1]
  3. so a huge number of strong covalent bonds must be broken — very high melting point[1]
  4. First ionisation energy generally increases across the period[1]
  5. because nuclear charge increases while shielding stays similar[1]
  6. so the outer electron is held more tightly and needs more energy to remove[1]

Melting point rises to a giant-covalent peak at Si then falls to molecular Ar; first ionisation energy rises (more nuclear charge, similar shielding).

Examiner tip. Melting point follows structure (metallic → giant covalent → molecular); ionisation energy follows nuclear pull.