The arrangement is not arbitrary
Elements are laid out in order of atomic number, but the genius of the table is the wrapping: each row (a period) fills one more electron shell, and each column (a group) collects elements with the same number of outer-shell electrons. Because chemistry is decided by outer electrons, a group is a family that behaves alike.
Metals sit on the left and centre, non-metals on the right, with a staircase of semi-metals between. The group number (for the main groups) tells you the valence electrons directly — group 1 has one, group 7 has seven.
Switch between the properties and watch the pattern: metals to the left, reactivity and size building toward the bottom-left for metals and the top-right for non-metals.
Group 1 — the alkali metals
Lithium, sodium, potassium: one outer electron they lose easily, so they are very reactive metals, stored under oil and forming +1 ions. React with water to give a hydroxide and hydrogen: 2Na + 2H₂O → 2NaOH + H₂.
The key trend: reactivity increases down the group. Lower down, the outer electron is further from the nucleus and more shielded, so it is lost more easily — potassium reacts far more violently than lithium.
Group 7 — the halogens
Fluorine, chlorine, bromine, iodine: seven outer electrons, needing just one more, so they are reactive non-metals forming −1 ions. They exist as diatomic molecules (Cl₂, Br₂).
Their trend runs the opposite way: reactivity decreases down the group, because gaining an electron gets harder as the outer shell sits further out. This gives displacement: a more reactive halogen pushes a less reactive one out of its salt — chlorine displaces bromine from potassium bromide.
Metals and non-metals trend in opposite directions
Metals get MORE reactive down a group (easier to lose an electron); non-metals get LESS reactive down a group (harder to gain one). The same cause — the outer shell moving away from the nucleus — helps a metal and hinders a non-metal.
Group 0 and the transition metals
Group 0 — the noble gases have a full outer shell, so they are unreactive (inert) and exist as single atoms. That stability is why they are used where you need something that will not react: argon in light bulbs, helium in balloons.
The transition metals in the centre are the "typical metals" — hard, dense, high melting points — but with extras: they form ions of more than one charge (Fe²⁺ and Fe³⁺), their compounds are often coloured, and many act as catalysts (iron in the Haber process).
A worked example
Predict: (a) is potassium more or less reactive than sodium? (b) will chlorine displace iodine from potassium iodide?
- (a) Both are group 1 metals; potassium is further down, so its outer electron is lost more easily.Group 1 reactivity increases down the group.
- Potassium is MORE reactive than sodium.Further from the nucleus and more shielded → electron lost more readily.
- (b) Chlorine is higher in group 7 than iodine, so it is the more reactive halogen.Group 7 reactivity decreases down the group.
- Yes — chlorine displaces iodine: Cl₂ + 2KI → 2KCl + I₂ (the solution darkens as iodine forms).A more reactive halogen displaces a less reactive one from its salt.
(a) Potassium is more reactive; (b) yes, chlorine displaces iodine, forming potassium chloride and iodine.
Why the pattern repeats
The periodic table works because chemistry is decided by outer-shell electrons. Each new period starts a new shell, and across the period that shell fills up — so the same outer arrangements recur, and with them the same kinds of chemistry. The group number equals the number of outer electrons, and the period number equals the number of occupied shells.
That single idea explains everything else on the table: why Group 1 metals all react the same way, why Group 0 is inert, and why reactivity trends run the way they do.
Trends across a period (A Level)
Move across Period 3 (Na → Ar) and clear trends appear. Atomic radius decreases: the nuclear charge rises while electrons enter the same shell, pulling everything in tighter. First ionisation energy generally rises for the same reason, with small dips where a new sub-shell or a paired orbital begins.
Melting point rises to a peak at silicon then collapses: Na, Mg and Al are metallic (rising with more delocalised electrons), silicon is a giant covalent structure (very high), while P₄, S₈, Cl₂ and Ar are simple molecular or atomic with only weak forces (very low).
| Element (Period 3) | Structure / bonding | Melting point trend |
|---|---|---|
| Na, Mg, Al | giant metallic | rises (more delocalised electrons) |
| Si | giant covalent | very high (peak) |
| P, S, Cl, Ar | simple molecular / atomic | low (weak van der Waals forces) |
Another worked example
Explain why the atomic radius of the elements decreases across Period 3 from sodium to chlorine.
- Across the period, the number of protons in the nucleus increases.Each element has one more proton than the last.
- The extra electrons are added to the same outer shell.The shell number does not change across a period.
- So the shielding stays roughly the same while the nuclear charge rises.Same inner shells, more nuclear pull.
- The greater nuclear attraction pulls the outer shell in closer, so the atomic radius decreases.Stronger pull with similar shielding contracts the atom.
Increasing nuclear charge with almost constant shielding pulls the outer electrons in more strongly, so the atoms get smaller across the period.