ChemistryAdvanced20 min read

Aromatic Hydrocarbons

Benzene, its delocalised ring, and why it substitutes instead of adding

This topic appears in:

Practise the full question bank:

01

The benzene ring

Benzene, C₆H₆, is a ring of six carbons — but it is not simply a ring of alternating double and single bonds. Its six extra p electrons are delocalised into a ring above and below the plane, so all six carbon–carbon bonds are identical, intermediate between single and double. That delocalisation makes benzene unusually stable ("aromatic"), far less reactive than an alkene.

This is why the Kekulé "alternating double bonds" picture is only a shorthand; the real structure is the delocalised ring, often drawn as a hexagon with a circle inside.

02

It substitutes, not adds

An alkene readily undergoes addition, which would break its double bond — but for benzene, addition would destroy the stable delocalised ring, which is energetically costly. So benzene instead undergoes electrophilic substitution: an electrophile replaces a hydrogen on the ring, and the aromatic system is preserved.

This single principle — keep the ring, swap an H — governs all of benzene's reactions.

Alkene vs arene, in one line

An alkene ADDS (its double bond is reactive and expendable). Benzene SUBSTITUTES (its delocalised ring is stable and worth preserving). Same electrophiles, opposite outcome.

03

The key substitution reactions

Each is an electrophilic substitution putting a new group on the ring in place of an H:

ReactionReagent / electrophileProduct
Nitrationconc. HNO₃ / conc. H₂SO₄ (NO₂⁺)nitrobenzene
HalogenationCl₂ or Br₂ with a halogen carrier (e.g. FeCl₃)chlorobenzene
Alkylation (Friedel–Crafts)haloalkane + AlCl₃an alkylbenzene (e.g. methylbenzene)
Sulfonationfuming sulfuric acidbenzenesulfonic acid
04

Why it matters

Aromatic compounds are everywhere in industry and biology — dyes, explosives (TNT is trinitrotoluene), drugs (aspirin, paracetamol), and plastics (polystyrene from styrene). Benzene derivatives like toluene and phenol are major feedstocks, so its substitution chemistry is worth knowing well.

05

A worked example

Worked example

Ethene reacts with bromine by addition, but benzene does not readily add bromine. Explain the difference.

  1. Ethene has a localised C=C double bond that is reactive; bromine adds across it, breaking the double bond.Addition is favourable for an alkene — the product is stable.
  2. Benzene's electrons are delocalised into a stable aromatic ring.The ring is much more stable than a set of alternating double bonds.
  3. Adding bromine would destroy that delocalised ring, which is energetically unfavourable, so benzene resists addition.Losing aromatic stability costs more energy than addition releases.
  4. With a halogen carrier, benzene instead undergoes substitution, keeping the ring.Substitution preserves the stable aromatic system.

Ethene adds bromine (reactive localised double bond); benzene resists addition because it would destroy its stable delocalised ring, so it substitutes instead.

06

How electrophilic substitution works

Benzene's reactions follow one mechanism: electrophilic substitution. First a strong electrophile is generated — in nitration, concentrated sulfuric acid protonates nitric acid to make the nitronium ion, NO₂⁺. The electron-rich ring then attacks the electrophile, briefly disrupting the delocalised system, before losing an H⁺ to restore the stable ring. Restoring that aromatic stability is the driving force for substituting rather than adding.

The catalyst is regenerated at the end, and the net result is one hydrogen on the ring swapped for the new group.

07

Friedel–Crafts and comparing reactivity

Two important variants build carbon–carbon bonds onto the ring: Friedel–Crafts alkylation (a haloalkane with an AlCl₃ catalyst adds an alkyl group) and acylation (an acyl chloride adds an acyl group). Both make the electrophile with a halogen-carrier catalyst.

Reactivity differs across related molecules: an alkene adds readily because its localised C=C is reactive; benzene is far less reactive and only substitutes; while phenol is more reactive than benzene, because the oxygen's lone pair feeds electron density into the ring — so phenol even decolourises bromine water without a catalyst.

Why phenol beats benzene

Phenol's –OH lone pair delocalises into the ring, making it more electron-rich and so more reactive toward electrophiles than benzene — it brominates three times over with bromine water alone.

Practice questions

6 questions · 22 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 10 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Describe the bonding in a benzene molecule.
Model answer

A ring of six carbons with six delocalised electrons spread above and below the ring; all six C–C bonds are identical, between single and double.

Examiner tip. Delocalisation makes benzene unusually stable.

SQ2[2 marks]
Explain why benzene undergoes substitution rather than addition reactions.
Model answer

Addition would destroy the stable delocalised ring; substitution replaces a hydrogen and preserves the aromatic stability.

Examiner tip. The stable delocalised ring is "worth keeping", so benzene substitutes.

SQ3[3 marks]
State the reagents and product for the nitration of benzene, and name the type of mechanism.
Model answer

Concentrated nitric acid with concentrated sulfuric acid (generating NO₂⁺) gives nitrobenzene, by electrophilic substitution.

Examiner tip. The H₂SO₄ generates the NO₂⁺ electrophile that attacks the ring.

SQ4[3 marks]
Describe how the electrophile is generated in the nitration of benzene, and state the overall reaction type.
Model answer

Concentrated sulfuric acid protonates concentrated nitric acid, which loses water to form the nitronium ion, NO₂⁺. This electrophile substitutes onto the ring, so the reaction is electrophilic substitution.

Examiner tip. H₂SO₄ is the catalyst that generates the NO₂⁺ electrophile.

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
Benzene reacts by electrophilic substitution.
  1. Explain why benzene is more stable than the hypothetical molecule cyclohexatriene (with three separate double bonds). [2]
  2. Give the reagents and conditions for the chlorination of benzene. [2]
  3. State why benzene does not decolourise bromine water, unlike an alkene. [2]
Mark scheme
  1. Benzene's electrons are delocalised around the ring[1]
  2. which lowers its energy / makes it more stable than isolated double bonds[1]
  3. Chlorine (Cl₂) with a halogen carrier catalyst[1]
  4. such as anhydrous AlCl₃ or FeCl₃[1]
  5. Benzene has no localised C=C double bond to undergo addition[1]
  6. its delocalised, stable ring does not react with bromine water[1]

Delocalisation lowers benzene's energy (extra stability); chlorination needs Cl₂ + AlCl₃/FeCl₃; no localised C=C means no addition, so bromine water is not decolourised.

Examiner tip. The lack of a reactive localised double bond is why benzene fails the alkene test.

LQ2[6 marks]
Benzene and phenol both react with electrophiles.
  1. Explain why benzene undergoes substitution rather than addition. [3]
  2. Explain why phenol is more reactive than benzene, and state what you would see when phenol is added to bromine water. [3]
Mark scheme
  1. Benzene has a stable delocalised ring of electrons[1]
  2. addition would destroy that stability, which is unfavourable[1]
  3. substitution replaces an H and restores the stable ring[1]
  4. In phenol the –OH lone pair delocalises into the ring[1]
  5. making the ring more electron-rich / more reactive to electrophiles[1]
  6. with bromine water the orange colour disappears and a white precipitate (2,4,6-tribromophenol) forms[1]

Benzene substitutes to keep its stable ring; phenol is more reactive (–OH lone pair enriches the ring) and decolourises bromine water, forming a white precipitate.

Examiner tip. Electron-donating groups activate the ring toward electrophilic substitution.