ChemistryAdvanced24 min read

Fundamentals of Organic Chemistry

Functional groups, naming, isomerism and reaction types

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01

Why carbon, and homologous series

Organic chemistry is the chemistry of carbon compounds. Carbon is unique because it forms four strong covalent bonds and bonds to itself in endless chains and rings, so millions of compounds are possible. To keep them manageable, they are grouped into homologous series — families sharing the same functional group (the reactive part) and a general formula, with each member differing from the next by CH₂.

The functional group, not the carbon skeleton, dictates a molecule's reactions — so learning families (alkanes, alkenes, alcohols, carboxylic acids…) means learning chemistry once and applying it to thousands of compounds.

02

Naming (IUPAC)

Systematic names are built from three parts: a stem for the number of carbons (meth-1, eth-2, prop-3, but-4, pent-5…), a suffix for the functional group (-ane, -ene, -ol, -oic acid…), and prefixes with locant numbers for branches and substituents. So 2-methylbutan-1-ol tells you the chain length, where the branch is, and which functional group sits where.

03

Isomerism

Isomers share a molecular formula but differ in structure. Structural isomers differ in how the atoms are connected — a different chain, branch position, or functional group (butane vs 2-methylpropane). Stereoisomers have the same connectivity but a different arrangement in space; the common school case is geometric (cis–trans) isomerism around a C=C double bond, which cannot rotate freely.

Isomerism matters because isomers can behave completely differently despite the same formula.

04

Reaction types and bond breaking

Most organic reactions fall into a few types: addition (atoms add across a double bond), substitution (one group replaces another), elimination (a small molecule is removed to form a double bond), and oxidation/reduction.

How a bond breaks decides the mechanism. Homolytic fission splits a bond evenly, giving free radicals (each atom keeps one electron); heterolytic fission splits it unevenly, giving ions — a nucleophile (electron-pair donor, attacks positive centres) or an electrophile (electron-pair acceptor, attacks negative centres).

The shortcut through all of organic chemistry

You never learn every compound — you learn functional groups. Every member of a homologous series reacts the same way, so mastering alkenes or alcohols once lets you predict thousands of reactions.

05

A worked example

Worked example

C₄H₁₀ has two isomers. Name them and say what kind of isomerism this is.

  1. One is a straight chain of four carbons: butane.All four carbons in one unbranched chain.
  2. The other has a three-carbon chain with a methyl branch on the middle carbon: 2-methylpropane.Same atoms (C₄H₁₀), connected differently — a branch.
  3. They have the same molecular formula but different connectivity — structural (chain) isomerism.Structural isomers differ in how the atoms are joined.

Butane and 2-methylpropane — structural (chain) isomers: same formula C₄H₁₀, different carbon skeleton.

06

Reaction mechanisms

A mechanism shows how a reaction happens, step by step, by tracking pairs of electrons. Bonds break either homolytically (one electron to each atom, making radicals — as in the chlorination of alkanes in UV light) or heterolytically (both electrons to one atom, making ions).

The attacking species has a name that matches the target: a nucleophile is electron-rich and attacks electron-poor carbon (as in the substitution of a haloalkane by OH⁻), while an electrophile is electron-poor and attacks electron-rich sites like the C=C double bond (as in the addition of bromine to an alkene). Curly arrows in a mechanism always show the movement of an electron pair.

07

Stereoisomerism

Structural isomers differ in how atoms are connected; stereoisomers have the same connections but a different arrangement in space. Geometric (cis–trans, or E/Z) isomerism arises at a C=C double bond, because there is no rotation about it — so groups are locked on the same side (cis/Z) or opposite sides (trans/E).

Optical isomerism occurs when a carbon carries four different groups (a chiral centre): the molecule and its mirror image cannot be superimposed, like left and right hands. The two forms rotate plane-polarised light in opposite directions and can behave very differently in the body.

Why C=C locks the shape

A carbon–carbon double bond cannot rotate without breaking the π bond, so the groups on each carbon are fixed in place — that fixed geometry is what makes cis–trans isomers possible.

08

Organic synthesis: joining the routes

Real problems ask you to turn one compound into another, often in more than one step — so it pays to know the map of functional-group conversions. Alkenes are a common starting point: add water for an alcohol, or bromine for a dihalide. Alcohols are a hub too: oxidise a primary alcohol to an aldehyde and then a carboxylic acid, oxidise a secondary alcohol to a ketone, or dehydrate any alcohol back to an alkene.

Haloalkanes open still more doors — hydroxide gives an alcohol, cyanide adds a carbon to give a nitrile, ammonia gives an amine. Planning a synthesis means picking the shortest sequence of these steps, each with the right reagent and conditions.

FromToReagent / conditions
Alkenealcoholsteam + acid catalyst (hydration)
Alkenedihaloalkaneadd a halogen (e.g. Br₂)
Haloalkanealcoholwarm aqueous NaOH
Haloalkanenitrile (+1 C)KCN in ethanol
Primary alcoholaldehyde → acidacidified dichromate, oxidise
Alcoholalkenehot Al₂O₃ or conc. H₂SO₄ (dehydration)
Carboxylic acidesteralcohol + conc. H₂SO₄

Practice questions

7 questions · 27 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 9 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Define the terms structural isomers.
Model answer

Compounds with the same molecular formula but different structural arrangements of their atoms.

Examiner tip. Same formula, different structure — e.g. butane and methylpropane (C₄H₁₀).

SQ2[2 marks]
Give the IUPAC name of the compound CH₃CH₂CH₂OH and state its functional group.
Model answer

Propan-1-ol; the functional group is the hydroxyl group, –OH (an alcohol).

Examiner tip. Name = stem (chain length) + suffix (functional group); a 3-carbon alcohol is propanol.

SQ3[3 marks]
Distinguish between homolytic and heterolytic bond fission, naming the species formed.
Model answer

In homolytic fission each atom takes one electron, forming two radicals. In heterolytic fission one atom takes both electrons, forming a positive and a negative ion.

Examiner tip. Homolytic → radicals; heterolytic → ions (one atom keeps the pair).

SQ4[2 marks]
Explain why but-2-ene shows cis–trans isomerism but butane does not.
Model answer

But-2-ene has a C=C double bond, and there is no rotation about it, so the methyl groups are fixed either on the same side (cis) or opposite sides (trans). Butane has only single bonds, which rotate freely, so no fixed arrangement — and no cis–trans isomers.

Examiner tip. Cis–trans needs a C=C double bond to lock the geometry.

Long questions

3 · 18 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
Organic reactions are classified by the type of change and the attacking species.
  1. Explain the difference between an electrophile and a nucleophile. [2]
  2. State the type of reaction (addition, substitution or elimination) when: bromine reacts with ethene; and a haloalkane forms an alkene with hot alcoholic KOH. [2]
  3. Explain what is meant by a functional group. [2]
Mark scheme
  1. An electrophile is an electron-pair acceptor (electron-poor species)[1]
  2. A nucleophile is an electron-pair donor (electron-rich species)[1]
  3. Bromine + ethene is an addition reaction[1]
  4. Haloalkane with hot alcoholic KOH is an elimination reaction[1]
  5. A functional group is the atom or group of atoms[1]
  6. that gives a molecule its characteristic chemical properties[1]

Electrophile accepts an electron pair, nucleophile donates one; Br₂ + ethene = addition, elimination gives the alkene; functional group = the reactive part defining the chemistry.

Examiner tip. Nucleophiles attack electron-poor carbons; electrophiles attack electron-rich sites like C=C.

LQ2[6 marks]
Organic reactions can be classified by mechanism.
  1. Define the terms nucleophile and electrophile. [2]
  2. State the type of species that attacks, and the reaction type, when: (i) bromine reacts with ethene; (ii) hydroxide reacts with bromoethane. [4]
Mark scheme
  1. A nucleophile is an electron-pair donor (electron-rich)[1]
  2. an electrophile is an electron-pair acceptor (electron-poor)[1]
  3. (i) Bromine acts as an electrophile[1]
  4. in an electrophilic addition to the C=C double bond[1]
  5. (ii) Hydroxide acts as a nucleophile[1]
  6. in a nucleophilic substitution of the haloalkane[1]

Nucleophile = electron-pair donor, electrophile = acceptor; Br₂/ethene = electrophilic addition; OH⁻/bromoethane = nucleophilic substitution.

Examiner tip. Match the attacking species to the site: electrophiles hit C=C, nucleophiles hit δ+ carbon.

LQ3[6 marks]
Show how you would carry out the following conversions, giving the reagents and conditions for each step.
  1. Ethene into ethanoic acid (two steps). [4]
  2. Bromoethane into propanenitrile, and state why this conversion is useful. [2]
Mark scheme
  1. Step 1: hydrate ethene with steam and an acid catalyst to give ethanol[1]
  2. (~300 °C, ~60 atm, phosphoric acid)[1]
  3. Step 2: oxidise the ethanol with acidified potassium dichromate[1]
  4. under reflux, to give ethanoic acid[1]
  5. React bromoethane with potassium cyanide in ethanol to give propanenitrile[1]
  6. useful because it adds a carbon, lengthening the chain[1]

Ethene → ethanol (steam + acid catalyst) → ethanoic acid (oxidise with acidified dichromate, reflux); bromoethane + KCN → propanenitrile (adds a carbon).

Examiner tip. Break a synthesis into functional-group steps and quote the reagent AND conditions for each.