BiologyCore20 min read

Inheritance

Genes, alleles and how characteristics pass to the next generation

This topic appears in:

Practise the full question bank:

01

Genes and alleles

Characteristics are inherited through genes — sections of DNA on chromosomes that code for a feature. Most genes come in different versions called alleles; you inherit one of each pair from each parent. An allele can be dominant (shown even if only one copy is present, written with a capital letter) or recessive (shown only when both copies are recessive, written with a small letter).

02

Genotype and phenotype

The genotype is the alleles an organism carries; the phenotype is the characteristic you actually see. An organism with two identical alleles is homozygous (BB or bb); with two different alleles it is heterozygous (Bb). A heterozygote shows the dominant phenotype but can still pass on the recessive allele — it is a carrier.

TermMeaning
Dominant alleleshown with one copy (capital letter)
Recessive alleleshown only with two copies (small letter)
Homozygoustwo identical alleles (BB or bb)
Heterozygoustwo different alleles (Bb)
03

Punnett squares

A Punnett square predicts the offspring of a cross. You write each parent's two alleles, combine them in all four ways, and read off the ratio of genotypes and phenotypes. Crossing two heterozygotes (Bb × Bb), for example, gives offspring in the ratio 1 BB : 2 Bb : 1 bb — a 3 : 1 ratio of dominant to recessive phenotypes.

04

Sex determination

In humans, sex is decided by one pair of chromosomes: females are XX and males XY. Every egg carries an X; a sperm carries either an X or a Y. So the sperm decides the sex of the child, and a Punnett square of XX × XY gives a 50 : 50 chance of a boy or a girl.

Dominant hides, recessive needs two

A dominant allele shows even when paired with a recessive one. A recessive feature appears only when both alleles are recessive — which is why recessive traits can skip generations through carriers.

05

A worked example

Worked example

In pea plants, tall (T) is dominant to short (t). Two heterozygous tall plants (Tt) are crossed. Work out the ratio of tall to short offspring.

  1. Each parent is Tt, so each can pass on T or t.Gametes carry one allele each.
  2. Combine in a Punnett square: TT, Tt, Tt, tt.All four combinations of the parents' alleles.
  3. Genotypes: 1 TT : 2 Tt : 1 tt.Reading the four boxes.
  4. TT and Tt are tall (T dominant), tt is short, so phenotypes are 3 tall : 1 short.The dominant allele shows in any plant that has it.

The offspring are in a 3 : 1 ratio of tall to short plants.

06

Codominance and multiple alleles

Not every gene is a simple dominant-versus-recessive pair. In codominance, both alleles show in the heterozygote at once — as in the AB blood group, where both the A and B alleles are expressed. Some genes also have multiple alleles: human ABO blood group is controlled by three alleles (Iᴬ, Iᴮ and i), where Iᴬ and Iᴮ are codominant and both are dominant to i. This gives four possible blood groups (A, B, AB and O).

Codominant vs dominant

With a dominant allele, only one of the pair shows. With codominance, BOTH alleles show together in the heterozygote — like the A and B antigens in blood group AB.

07

Genetic disorders and pedigrees

Some diseases are inherited. A recessive disorder (such as cystic fibrosis) appears only when a person inherits two recessive alleles; a carrier has one and is healthy but can pass it on. A dominant disorder shows with just one faulty allele. A pedigree (family tree) diagram tracks a condition through the generations, and Punnett squares can then work out the risk of a child inheriting it — the basis of genetic counselling.

Practice questions

5 questions · 19 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 7 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[3 marks]
Define the terms allele, genotype and phenotype.
Model answer

Allele: a version of a gene. Genotype: the alleles an organism carries. Phenotype: the characteristic actually shown by the organism.

Examiner tip. Allele = version, genotype = alleles carried, phenotype = what you see.

SQ2[2 marks]
Explain how the sex of a human child is determined.
Model answer

The mother's egg always carries an X chromosome; the father's sperm carries either an X or a Y. If an X sperm fertilises the egg the child is XX (female); if a Y sperm does, the child is XY (male) — a 50:50 chance.

Examiner tip. The sperm's X or Y decides the sex.

SQ3[2 marks]
Explain the difference between a dominant allele and codominant alleles.
Model answer

A dominant allele is expressed even when paired with a recessive one, so only it shows. Codominant alleles are both expressed together in the heterozygote, so both features appear (as in blood group AB).

Examiner tip. Dominant hides the other; codominant both show.

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
In humans, the allele for brown eyes (B) is dominant to blue eyes (b). A heterozygous brown-eyed man and a blue-eyed woman have children.
  1. State the genotypes of both parents. [2]
  2. Use a genetic diagram to find the ratio of brown-eyed to blue-eyed children. [4]
Mark scheme
  1. The man is Bb (heterozygous brown)[1]
  2. the woman is bb (blue, homozygous recessive)[1]
  3. Man's gametes B and b; woman's gametes b and b[1]
  4. Offspring: Bb, Bb, bb, bb[1]
  5. genotypes 2 Bb : 2 bb[1]
  6. phenotype ratio 1 brown : 1 blue (50%)[1]

Parents Bb × bb; offspring 2 Bb : 2 bb = 1 brown : 1 blue.

Examiner tip. A cross with a homozygous recessive parent often gives a 1:1 ratio.

LQ2[6 marks]
Cystic fibrosis is caused by a recessive allele (f). Two parents who are both carriers (Ff) have children.
  1. State the genotypes of children who would have cystic fibrosis and who would be carriers. [2]
  2. Use a genetic diagram to find the probability that a child has cystic fibrosis. [4]
Mark scheme
  1. A child with cystic fibrosis is ff (homozygous recessive)[1]
  2. a carrier is Ff (heterozygous)[1]
  3. Parents Ff × Ff; gametes F and f from each[1]
  4. Offspring: FF, Ff, Ff, ff[1]
  5. genotypes 1 FF : 2 Ff : 1 ff[1]
  6. probability of cystic fibrosis (ff) = 1 in 4 (25%)[1]

Affected = ff, carrier = Ff; Ff × Ff gives 1 FF : 2 Ff : 1 ff, so a 1 in 4 chance of cystic fibrosis.

Examiner tip. Two carriers give the classic 3:1 ratio — 1 in 4 affected.