ChemistryAdvanced20 min read

Aldehydes & Ketones

The carbonyl group, and the tests that tell the two apart

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01

The carbonyl group

Both aldehydes and ketones contain the carbonyl group, C=O. The difference is where it sits. In an aldehyde the carbonyl is at the end of the chain, so the carbon also carries a hydrogen (–CHO). In a ketone it is in the middle, bonded to two carbon groups (R–CO–R). That single positional difference drives all their contrasting chemistry.

The C=O bond is polar (oxygen δ−, carbon δ+), so the carbonyl carbon is attacked by nucleophiles — nucleophilic addition is their characteristic reaction.

02

Oxidation splits them apart

The key distinction: aldehydes are easily oxidised to carboxylic acids (that terminal C–H is available to be removed), while ketones resist oxidation (no such hydrogen). This is exactly why a primary alcohol oxidises all the way to an acid but a secondary alcohol stops at a ketone.

That difference gives two classic tests to tell an aldehyde from a ketone.

03

The distinguishing tests

Both are mild oxidising agents that only the aldehyde reduces:

TestAldehydeKetone
Tollens' reagent (ammoniacal silver nitrate)silver mirror formsno change
Fehling's / Benedict's solutionblue → brick-red precipitatestays blue
Acidified dichromateorange → green (oxidised)no change
04

Reduction and uses

Both can be reduced (the reverse of the alcohol oxidation): an aldehyde back to a primary alcohol, a ketone to a secondary alcohol. In use, methanal (formaldehyde) makes resins and preservatives, and propanone (acetone) is a common solvent (nail-polish remover).

One test, clear answer

Tollens' reagent gives a silver mirror ONLY with an aldehyde. It is the quick, memorable way to distinguish an aldehyde from a ketone — the aldehyde reduces the silver ions to silver metal.

05

A worked example

Worked example

You have propanal (an aldehyde) and propanone (a ketone), both colourless liquids. How do you tell them apart with Tollens' reagent?

  1. Add Tollens' reagent (ammoniacal silver nitrate) to each and warm gently.Tollens' is a mild oxidising agent that only aldehydes reduce.
  2. Propanal (aldehyde) is oxidised and reduces the silver ions, depositing a silver mirror on the tube.Aldehydes are easily oxidised; the Ag⁺ is reduced to Ag metal.
  3. Propanone (ketone) does not react — no mirror.Ketones resist oxidation, so they cannot reduce the silver.

The one that forms a silver mirror is the aldehyde (propanal); the one that does nothing is the ketone (propanone).

06

Nucleophilic addition

The carbonyl group C=O is polar — the carbon is δ+ and the oxygen δ− — so its characteristic reaction is nucleophilic addition: a nucleophile attacks the carbon while the double bond opens onto the oxygen. Adding hydrogen cyanide (HCN), for example, gives a hydroxynitrile, lengthening the chain by one carbon.

Carbonyls are also readily reduced (e.g. with sodium borohydride, NaBH₄): an aldehyde becomes a primary alcohol and a ketone a secondary alcohol — exactly reversing the oxidation that made them.

07

Identifying carbonyls

A carbonyl compound is first confirmed with 2,4-dinitrophenylhydrazine (2,4-DNPH, Brady's reagent), which gives an orange precipitate with any aldehyde or ketone. Then you tell the two apart by oxidation: only an aldehyde reduces Tollens' reagent (a silver mirror) or Fehling's solution (a brick-red precipitate); a ketone does neither.

The iodoform (triiodomethane) test adds one more clue: a yellow precipitate with warm alkaline iodine indicates a methyl ketone (or ethanal), a group with the CH₃CO– arrangement.

TestAldehydeKetone
2,4-DNPHorange precipitateorange precipitate
Tollens' reagentsilver mirrorno change
Fehling's solutionbrick-red precipitateno change
Iodoform (if methyl carbonyl)yellow ppt (ethanal only)yellow ppt (methyl ketones)

Practice questions

6 questions · 21 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

4 · 9 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State the difference in structure between an aldehyde and a ketone.
Model answer

Both contain the carbonyl group C=O; in an aldehyde it is at the end of the chain (–CHO), in a ketone it is in the middle, bonded to two carbon groups.

Examiner tip. Aldehyde carbonyl is terminal (has an H); ketone carbonyl is internal.

SQ2[2 marks]
Describe a chemical test that distinguishes an aldehyde from a ketone.
Model answer

Warm with Tollens' reagent: an aldehyde forms a silver mirror; a ketone gives no change.

Examiner tip. Only aldehydes are easily oxidised, so only they reduce the silver ions.

SQ3[3 marks]
State the type of reaction and the product when propanal is reduced.
Model answer

Reduction (e.g. with NaBH₄) gives propan-1-ol; the carbonyl C=O is reduced to a C–OH group (a primary alcohol).

Examiner tip. Aldehyde → primary alcohol; ketone → secondary alcohol on reduction.

SQ4[2 marks]
State the reagent and the products when propanal and propanone are each reduced.
Model answer

Reduction (e.g. with NaBH₄): propanal (an aldehyde) gives propan-1-ol (a primary alcohol); propanone (a ketone) gives propan-2-ol (a secondary alcohol).

Examiner tip. Aldehyde → primary alcohol; ketone → secondary alcohol.

Long questions

2 · 12 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
A student has two unlabelled bottles, one containing propanal and one containing propanone.
  1. Describe the result of adding Fehling's solution to each, on warming. [3]
  2. State the characteristic reaction type of the carbonyl group and why the carbon is attacked. [3]
Mark scheme
  1. Propanal (aldehyde) gives a positive result[1]
  2. the blue solution forms a brick-red precipitate[1]
  3. Propanone (ketone) gives no change (stays blue)[1]
  4. The characteristic reaction is nucleophilic addition[1]
  5. The C=O bond is polar with a δ+ carbon[1]
  6. so nucleophiles are attracted to and attack the carbonyl carbon[1]

Aldehyde → brick-red precipitate with Fehling's; ketone → stays blue; carbonyl undergoes nucleophilic addition at its δ+ carbon.

Examiner tip. Fehling's/Tollens' distinguish aldehydes (oxidised) from ketones (not).

LQ2[6 marks]
A student has two unlabelled liquids: one is an aldehyde, the other a ketone.
  1. Describe a test that shows both are carbonyl compounds. [2]
  2. Describe a test, with results, that distinguishes the aldehyde from the ketone. [4]
Mark scheme
  1. Add 2,4-DNPH (Brady's reagent) to each[1]
  2. both give an orange precipitate, confirming a carbonyl group[1]
  3. Warm each with Tollens' reagent (ammoniacal silver nitrate)[1]
  4. the aldehyde forms a silver mirror[1]
  5. the ketone gives no change[1]
  6. (alternatively Fehling's: aldehyde gives a brick-red precipitate, ketone stays blue)[1]

2,4-DNPH gives an orange precipitate with both (carbonyl present); Tollens' gives a silver mirror only with the aldehyde.

Examiner tip. Confirm the carbonyl first (2,4-DNPH), then distinguish by oxidation (Tollens'/Fehling's).