MathematicsFoundation20 min read

Indices, Roots and Standard Form

The laws of powers, and a way to write numbers too big to say

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01

An index is a count of how many times

2⁵ means 2 multiplied by itself five times. The 2 is the base and the 5 is the index, power or exponent — three words for the same thing, all of which appear in exam questions.

Every law below follows from that definition, which is why they are worth deriving once rather than memorising six separate rules. 2³ × 2⁴ is three 2s multiplied by four 2s, which is seven 2s — so the indices add.

aᵐ × aⁿ = aᵐ⁺ⁿaᵐ ÷ aⁿ = aᵐ⁻ⁿ(aᵐ)ⁿ = aᵐⁿ(ab)ⁿ = aⁿbⁿa⁰ = 1a⁻ⁿ = 1 / aⁿa^(1/n) = ⁿ√aa^(m/n) = (ⁿ√a)ᵐthe laws apply only when the BASES are the same — 2³ × 3⁴ simplifies to nothing

Why a⁰ = 1 and why a negative index means a reciprocal

Follow the division law downwards: 2³ ÷ 2³ = 2⁰, and anything divided by itself is 1 — so 2⁰ = 1. Continue: 2³ ÷ 2⁵ = 2⁻², and cancelling gives 1/2² — so a negative index means one over. Neither is an arbitrary convention; both are forced by the law that was already there.

02

Fractional indices are roots

What could 9^(1/2) mean? Whatever it is, the multiplication law says 9^(1/2) × 9^(1/2) = 9¹ = 9. So it is the number that multiplies by itself to give 9 — the square root, 3.

The same argument gives a^(1/3) as the cube root, and generally a^(1/n) = ⁿ√a. For a general fraction, take the root first and then the power: 8^(2/3) means the cube root of 8, which is 2, then squared, giving 4. Rooting first keeps the numbers small.

Worked example

Evaluate 16^(3/4), 5⁻² and (2⁻³)⁻² without a calculator.

  1. 16^(3/4): the denominator 4 is the root, so take the fourth root of 16 first, which is 2.Rooting first keeps the arithmetic small — 16³ would be 4096 before you even started.
  2. Then raise to the numerator: 2³ = 8.
  3. 5⁻² = 1/5² = 1/25.The minus sign means reciprocal, not a negative answer. 5⁻² is not −25.
  4. (2⁻³)⁻² = 2^(−3 × −2) = 2⁶ = 64.The power law multiplies the indices, and two negatives give a positive.

16^(3/4) = 8; 5⁻² = 1/25; (2⁻³)⁻² = 64

A negative index never gives a negative answer

3⁻² = 1/9, which is positive and small. Students write −9 remarkably often. The index sign controls whether you go up or down — it has nothing to do with the sign of the result.

03

Standard form

The distance to the sun is about 150 000 000 000 metres, and the diameter of an atom about 0.0000000001 m. Both are unreadable, and counting the zeros is where the mistakes happen.

Standard form writes every number as a × 10ⁿ, where 1 ≤ a < 10 and n is an integer. Those two conditions are the whole definition, and both are marked: 15 × 10¹⁰ is arithmetically correct but not in standard form, because 15 is not below 10.

a × 10ⁿwith 1 ≤ a < 10150 000 000 000 = 1.5 × 10¹¹0.000 000 000 1 = 1 × 10⁻¹⁰a positive index means a large number, a negative index a small one — the index counts places, not zeros
Worked example

Work out (3.2 × 10⁵) × (4 × 10⁻³), giving the answer in standard form.

  1. Multiply the number parts: 3.2 × 4 = 12.8.Handle the digits and the powers separately — that is what standard form is for.
  2. Add the indices: 10⁵ × 10⁻³ = 10².The multiplication law, with a negative index simply subtracting.
  3. So far 12.8 × 10² — correct, but not standard form.12.8 is not between 1 and 10, so one more step is needed.
  4. Adjust: 12.8 = 1.28 × 10¹, so the answer is 1.28 × 10³.Moving the point one place left increases the index by one. Check: 1280 ✓

1.28 × 10³

04

Powers, roots and the calculator

The syllabus expects square and cube numbers up to reasonable limits to be known by sight, because recognising them is what makes estimation and factorising quick. Squares to 15², cubes to 5³, and the square roots that follow from them.

Beyond that, the calculator handles it — but only if the expression is entered with the brackets the mathematics requires. √(9 + 16) is 5; √9 + 16 is 19. The root sign in handwriting extends over everything beneath it, and that grouping must be typed in as brackets.

Before you leave this chapter

  1. Multiplying adds indices, dividing subtracts, a power of a power multiplies — but only for the same base.
  2. a⁰ = 1 and a⁻ⁿ = 1/aⁿ, both forced by the division law.
  3. a^(m/n) means the n-th root, then the m-th power. Root first.
  4. Standard form is a × 10ⁿ with 1 ≤ a < 10. Both conditions are marked.
  5. The bar of a root sign is a bracket — type it as one.
05

Why exponential growth outruns everything

A quantity that grows by a fixed amount each step follows a straight line. One that grows by a fixed factor follows an exponential curve, and the difference between them is enormous over any length of time.

Doubling repeatedly is the clearest case. Start with one rupee and double it every day: after ten days it is Rs 1024, after twenty it is over a million, after thirty it is more than a billion. Nothing about the first few days suggests where it ends up, which is why exponential growth is so consistently underestimated.

Switch between Linear, Quadratic and Exponential. Near the origin the exponential looks unremarkable; a little further out it has left the others behind entirely, and no polynomial ever catches it.

The rule of 72

A quantity growing at r% per period roughly doubles every 72 ÷ r periods. At 8% that is about 9 years; at 12%, about 6. It is an approximation rather than a formula to quote in an answer, but it is a fast sanity check on any compound growth calculation — and it works because of the index laws in this chapter.

Practice questions

6 questions · 20 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Simplify (x³)⁴ ÷ x⁵.
Model answer

(x³)⁴ = x¹² by the power law, then x¹² ÷ x⁵ = x⁷ by subtracting the indices.

Examiner tip. Do the bracket first. Adding 3 and 4 instead of multiplying them is the standard error and gives x² instead of x⁷.

SQ2[2 marks]
Write 0.000 402 in standard form.
Model answer

The first significant figure is 4, so a = 4.02. The point moves four places right to get there, so n = −4: 4.02 × 10⁻⁴.

Examiner tip. Count places moved, not zeros. Here there are three zeros after the point but the index is −4.

SQ3[2 marks]
Evaluate 27^(2/3).
Model answer

The cube root of 27 is 3, and 3² = 9.

Examiner tip. Root first, then power. Cubing 27 first gives 19 683, whose cube root you then have to find — same answer, far more work.

Solved numericals

2 · 8 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
Simplify, leaving your answer in index form: (2a²b)³ × (4a⁻¹b²) ÷ (8a³b⁴).
Full working
  1. (2a²b)³ = 8a⁶b³ — every factor inside the bracket is cubed, including the 2forgetting to cube the 2 is the usual slip[1]
  2. Multiply: 8a⁶b³ × 4a⁻¹b² = 32a⁵b⁵coefficients multiply, indices add[1]
  3. Divide: 32 ÷ 8 = 4, and indices subtract[1]
  4. = 4a²ba⁵⁻³ = a², b⁵⁻⁴ = b¹[1]

4a²b

Examiner tip. Deal with the numbers and each letter separately, in three passes. Trying to do all three at once is where terms go missing.

N2[4 marks]
Light travels at 3 × 10⁸ m/s. Calculate the distance it covers in one year of 3.15 × 10⁷ seconds, in standard form to 3 significant figures.
Full working
  1. Distance = speed × time = (3 × 10⁸) × (3.15 × 10⁷)[1]
  2. Number parts: 3 × 3.15 = 9.45[1]
  3. Indices: 10⁸ × 10⁷ = 10¹⁵add the indices[1]
  4. = 9.45 × 10¹⁵ m, already in standard form9.45 lies between 1 and 10, so no adjustment is needed[1]

9.45 × 10¹⁵ metres

Examiner tip. Always check the final number part is between 1 and 10. Here it happens to be; when it is not, adjusting it is a separate mark.

Long questions

1 · 6 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
A single grain of sand has a mass of 1.5 × 10⁻⁵ kg.
  1. Find the mass of 2 × 10⁶ grains, in standard form.
  2. A beach contains 8 × 10¹⁸ grains. Find its total mass in kilograms.
  3. Express that mass in tonnes, given 1 tonne = 1000 kg, in standard form.
Mark scheme
  1. (1.5 × 10⁻⁵) × (2 × 10⁶) = 3 × 10¹1.5 × 2 = 3 and −5 + 6 = 1[1]
  2. = 30 kgaccept either form[1]
  3. (1.5 × 10⁻⁵) × (8 × 10¹⁸) = 12 × 10¹³[1]
  4. Adjusted to standard form: 1.2 × 10¹⁴ kg12 is not between 1 and 10[1]
  5. Divide by 1000, that is by 10³: subtract 3 from the index[1]
  6. = 1.2 × 10¹¹ tonnes[1]

(a) 3 × 10¹ kg (b) 1.2 × 10¹⁴ kg (c) 1.2 × 10¹¹ tonnes

Examiner tip. Converting units in standard form is just a change to the index: dividing by 10³ subtracts 3. There is no need to write the number out in full.