PhysicsCore26 min read

Physical Optics and Gravitational Waves

Interference, diffraction, polarisation — and waves in spacetime itself

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01

Superposition and coherence

Definition

Principle of superposition — When two waves meet, the resultant displacement at any point is the vector sum of their individual displacements.

Waves do not collide and bounce off each other. They pass straight through, and where they overlap the displacements simply add. Two crests meeting give a bigger crest; a crest meeting a trough cancels.

Where the result is larger the waves are said to interfere constructively; where they cancel, destructively. Which happens depends on the path difference — how much further one wave has travelled than the other.

A path difference of a whole number of wavelengths means the waves arrive in step and reinforce. A path difference of an odd number of half-wavelengths means they arrive exactly out of step and cancel.

For a stable pattern the sources must be coherent: the same frequency and a constant phase difference. Two separate light bulbs are not coherent, because each emits in random bursts, so no pattern is seen. This is why Young's experiment splits light from one source into two rather than using two lamps.

constructive: path difference = n λdestructive:path difference = (n + ½) λn is any whole number, including zero
λ
wavelengthm
n
order

Two waves drawn separately, then added. Slide the phase difference to 0° and the resultant is twice the height; slide it to 180° and it flattens to nothing. Everything in interference is that one picture, applied to light.

02

Young's double slit

Light through two narrow, closely spaced slits produces a pattern of bright and dark fringes on a distant screen. That is not something a particle model can explain, and it is the classic demonstration that light travels as a wave.

Each slit acts as a source. At the centre of the screen the two paths are equal, so the waves arrive in step and there is a bright fringe. Move to one side and one path grows longer than the other; when the difference reaches half a wavelength the waves cancel and there is a dark fringe; at a whole wavelength they reinforce again.

The spacing between fringes depends on the wavelength, the slit separation and the distance to the screen. It follows that red light gives wider fringes than blue, since red has the longer wavelength — and that using white light produces a white central fringe with coloured fringes either side, because each colour has its own spacing.

The fringes are very close together, which is why the slits must be narrow and close and the screen far away. That is also why the effect is not obvious in daily life.

λ = a x / Dx = λ D / ax is the fringe spacing, a the slit separation, D the distance to the screen
λ
wavelengthm
a
slit separationm
x
fringe spacingm
D
slit-to-screen distancem
Worked example 15 marks

Two slits 0.25 mm apart are lit by a laser. Fringes 4.7 mm apart appear on a screen 1.8 m away. Find the wavelength.

  1. Convert everything to metres: a = 2.5 × 10⁻⁴ m, x = 4.7 × 10⁻³ m.Mixed units are where nearly every lost mark in this topic comes from.
  2. Use λ = ax/D.
  3. λ = (2.5 × 10⁻⁴ × 4.7 × 10⁻³) / 1.8.
  4. λ = 1.175 × 10⁻⁶ / 1.8.
  5. λ = 6.5 × 10⁻⁷ m = 650 nm.Red light — plausible for a laser pointer, so the answer passes inspection.

6.5 × 10⁻⁷ m, about 650 nm — red

03

Diffraction and the grating

Diffraction is the spreading of a wave as it passes an edge or through a gap. The narrower the gap, the more the wave spreads, and the effect is greatest when the gap is about the same size as the wavelength.

This is why sound bends round a doorway and light does not: sound wavelengths are metres, comparable to a doorway, while visible light is around half a micrometre.

A diffraction grating has thousands of slits per centimetre rather than two. Many slits mean the bright fringes become very sharp and widely separated, which makes measurement far more precise than with a double slit.

Because the angle of each maximum depends on wavelength, a grating splits white light into a spectrum — and unlike a prism it does so by a calculable amount. That is why gratings are used in spectrometers to identify the elements in a star from the light it emits.

d sin θ = n λd = 1 / Nd is the slit spacing; if a grating has N lines per metre then d is its reciprocal
d
spacing between slitsm
θ
angle of the maximum°
n
order
N
lines per metrem⁻¹

sin θ can never exceed 1

If a calculation gives sin θ > 1 for some order, that order simply does not exist — the light cannot be diffracted that far. This is a common exam question: "how many orders are visible?" Work out the largest n for which nλ/d ≤ 1.

04

Polarisation

Light is a transverse wave, and the vibrations of an unpolarised beam happen in every direction perpendicular to the direction of travel. A polarising filter transmits only those vibrating in one plane, and the light that gets through is plane polarised.

Because only transverse waves can be polarised, the fact that light can be is direct evidence that it is transverse. Sound cannot be polarised, and that alone tells us sound is longitudinal.

Put two polarising filters in line and rotate one. At parallel orientation most light passes; at right angles almost none does. This is how polarising sunglasses cut glare: light reflected from water or a road is partly polarised horizontally, so a filter oriented vertically blocks it.

The same principle appears in photography, in stress analysis of transparent models, and in liquid crystal displays.

Key points

  1. Only transverse waves can be polarised — so polarisation proves light is transverse.
  2. Two filters at right angles block almost all the light.
  3. Reflected glare is partly polarised, which is what sunglasses exploit.
05

Gravitational waves

Einstein's general relativity describes gravity not as a force but as a curvature of spacetime. A consequence, predicted in 1916, is that violently accelerating masses should send ripples through spacetime itself — gravitational waves, travelling at the speed of light.

They are extraordinarily weak. A passing wave stretches space in one direction and squeezes it in the perpendicular direction, but by a fraction of about 10⁻²¹ — less than a thousandth of the width of a proton across a four-kilometre detector.

LIGO detects them with a laser interferometer built on exactly the interference principle earlier in this chapter. A laser beam is split down two perpendicular arms, reflected, and recombined. Normally the two paths cancel. A passing gravitational wave changes one arm's length relative to the other by a minute amount, the cancellation is no longer perfect, and light appears at the detector.

The first detection was in September 2015, from two black holes of about 29 and 36 solar masses merging over a billion light-years away. It confirmed a century-old prediction and opened a way of observing the universe that does not rely on light at all — which matters, because events like black hole mergers emit almost no light.

Why this belongs in an optics chapter

A gravitational wave detector is a double-slit experiment scaled up to four kilometres. The same superposition principle that makes fringes on a screen is what lets LIGO measure a change smaller than a proton. Interference is not a curiosity — it is the most sensitive measuring technique physics has.

Key points

  1. Coherent sources are needed for a stable interference pattern.
  2. Constructive at path difference, destructive at (n + ½)λ.
  3. λ = ax/D for the double slit; d sin θ = nλ for a grating.
  4. Diffraction is greatest when the gap is about one wavelength wide.
  5. Polarisation is possible only for transverse waves.
06

Stationary waves

When two waves of the same frequency travel in opposite directions through each other — usually an incident wave and its own reflection — they superpose into a pattern that does not travel at all. Certain points never move, and others oscillate with maximum amplitude, and neither set changes position.

The points that never move are nodes, where the two waves are permanently out of phase and cancel. Between them are antinodes, where they are permanently in phase and reinforce. The distance from one node to the next is half a wavelength, which is the fact nearly every calculation rests on.

Progressive waveStationary wave
Energytransferred along the wavenot transferred, only stored
Amplitudethe same for all pointsvaries from zero at nodes to maximum at antinodes
Phasechanges continuously along the waveall points between adjacent nodes are in phase
Wavelengthdistance between adjacent in-phase pointstwice the node-to-node distance

Node to node is half a wavelength

The commonest error is treating the node spacing as a full wavelength. Adjacent nodes are separated by λ/2, so a string vibrating with three nodes along its length holds one full wavelength, not three. Sketching the pattern and counting half-wavelengths between the ends is more reliable than trying to remember the rule.

Practice questions

6 questions · 24 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State what is meant by coherent sources, and why they are needed for interference.
Model answer

Sources with the same frequency and a constant phase difference. Without that, the phase relationship changes randomly and no stable pattern of fringes is seen.

Examiner tip. Both conditions — same frequency and constant phase difference. "Same wavelength" alone is not enough.

SQ2[2 marks]
Explain why light can be polarised but sound cannot.
Model answer

Light is a transverse wave, so its vibrations are perpendicular to the direction of travel and one plane can be selected. Sound is longitudinal, vibrating along the direction of travel, so there is no plane to select.

Examiner tip. This is the standard proof that light is transverse — say so.

SQ3[2 marks]
Explain why sound diffracts round a doorway but light does not.
Model answer

Diffraction is greatest when the gap is comparable to the wavelength. Sound wavelengths are around a metre, similar to a doorway, while visible light is about 5 × 10⁻⁷ m — far too small to spread noticeably.

Examiner tip. Quote the comparison of wavelength to gap size; that is the physics.

Solved numericals

1 · 5 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[5 marks]
A diffraction grating has 300 lines per millimetre. Light of wavelength 590 nm falls on it normally. Find the angle of the first order maximum, and the highest order visible.
Full working
  1. d = 1 / (300 × 10³) = 3.33 × 10⁻⁶ m300 per mm is 3 × 10⁵ per metre[1]
  2. Uses d sin θ = nλ with n = 1[1]
  3. sin θ = 590 × 10⁻⁹ / 3.33 × 10⁻⁶ = 0.177[1]
  4. θ = 10.2°[1]
  5. Highest order: n ≤ d/λ = 5.6, so n = 5sin θ cannot exceed 1[1]

θ = 10.2° for the first order; 5 orders visible

Examiner tip. Lines per millimetre must become lines per metre before taking the reciprocal. Getting d wrong by 10³ is the usual slip.

Long questions

1 · 8 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[8 marks]
In a double slit experiment, slits 0.40 mm apart are illuminated with light of wavelength 5.9 × 10⁻⁷ m. The screen is 2.4 m away.
  1. Explain why a bright fringe appears at the centre of the screen. [2]
  2. Calculate the fringe spacing. [3]
  3. State and explain what happens to the pattern if the slit separation is halved. [3]
Mark scheme
  1. The two paths to the centre are equal in length[1]
  2. So the path difference is zero, the waves arrive in phase and interfere constructively[1]
  3. Uses x = λD/a[1]
  4. x = (5.9 × 10⁻⁷ × 2.4) / 4.0 × 10⁻⁴[1]
  5. x = 3.5 × 10⁻³ m, about 3.5 mm[1]
  6. The fringe spacing doubles[1]
  7. Because x is inversely proportional to a[1]
  8. The fringes become more widely separated and easier to measure[1]

(b) 3.5 mm (c) spacing doubles

Examiner tip. Halving the slit separation doubles the spacing — the relationship is inverse. Students often assume the fringes get closer.

Exam questions

1 · 5 marks

Multi-part questions with a full mark scheme.

Q1[5 marks]
Gravitational waves were first detected in 2015 by LIGO, an instrument built on the interference of laser light.
  1. Explain how an interferometer detects an extremely small change in length. [3]
  2. State one reason gravitational wave astronomy sees events that telescopes cannot. [2]
Mark scheme
  1. A laser beam is split down two perpendicular arms and recombined[1]
  2. The arms are set so the returning beams cancel by destructive interference[1]
  3. A tiny change in one arm's length upsets the cancellation, so light appears at the detectora fraction of a wavelength is enough[1]
  4. Events such as black hole mergers emit almost no light[1]
  5. But they do radiate gravitational waves, which also pass through intervening dust and gas unimpeded[1]

Examiner tip. The point is sensitivity: interference converts a change far smaller than a wavelength into a change in brightness you can measure.