PhysicsCore25 min read

Oscillations and Simple Harmonic Motion

The one restoring-force condition that produces a sine wave in time

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01

The condition that defines it

Definition

Simple harmonic motion — Motion in which the acceleration is proportional to the displacement from a fixed point and always directed towards that point: a = −ω²x.

Not every repeating motion is simple harmonic. SHM is a specific and rather narrow case, defined by one condition on the acceleration: it must be proportional to the displacement from equilibrium, and directed back towards that equilibrium.

The minus sign in a = −ω²x carries the entire physical meaning. It says that whenever the object is displaced one way, the acceleration points the other. Remove the minus and you have exponential runaway, not oscillation.

Both parts of the condition are examined. "Acceleration proportional to displacement" alone is not enough for the marks — the direction must be stated too.

a = −ω²xthe defining conditionx = x₀ sin ωtorx = x₀ cos ωtv = ±ω√(x₀² − x²)v_max = ωx₀a_max = ω²x₀ω = 2πf = 2π/Tthe sine or cosine form is chosen by where the motion starts
ω
angular frequencyin rad s⁻¹, equal to 2πf
x₀
the amplitudethe maximum displacement from equilibrium
T
the periodindependent of amplitude, which is the striking feature

Change the amplitude and watch the period stay exactly the same — that independence is what makes a pendulum useful as a clock. Then change the mass and the stiffness, which do alter it.

02

Where the speed and the acceleration are largest

The two quantities peak at opposite ends of the motion, and getting this the right way round is worth several marks across a paper.

At maximum displacement the restoring force is largest, so the acceleration is maximum — but the object is momentarily stationary, so the speed is zero. At the equilibrium position there is no net force at all, so the acceleration is zero, yet this is exactly where the object is moving fastest.

The period of SHM does not depend on the amplitude. Pull a pendulum back further and it travels further, but proportionately faster, so it takes the same time. This property is called isochronism and it is why pendulums were used as clocks for three centuries.

PositionDisplacementVelocityAccelerationEnergy
equilibrium0maximum0all kinetic
maximum displacementx₀0maximumall potential
halfway (x = x₀/2)x₀/20.87 v_maxhalf of maxmostly kinetic
E_total = ½ m ω² x₀²constantE_k = ½ m ω² (x₀² − x²)E_p = ½ m ω² x²mass-spring: T = 2π√(m/k)simple pendulum: T = 2π√(L/g)neither period formula contains the amplitude
E_total
the total energyconstant if there is no damping
k
the spring constantstiffer spring means shorter period
L
the pendulum lengththe only thing you can change to alter its period

Energy goes as the amplitude squared

Doubling the amplitude does not double the energy — it quadruples it, since E ∝ x₀². The same squared relationship appears for the maximum speed being proportional to amplitude, so the kinetic energy at the centre scales with the square. Questions exploit this regularly.

03

Damping and resonance

Real oscillators lose energy to friction and air resistance, so the amplitude decays. This is damping, and how much of it is present changes the behaviour qualitatively rather than just quantitatively.

Light damping lets the system oscillate many times with a slowly shrinking amplitude. Critical damping returns it to equilibrium in the shortest possible time without overshooting — the behaviour a car suspension or a door closer is designed for. Heavy damping returns it slowly, without oscillating at all.

When a system is driven by a periodic force, the amplitude of its response depends on the driving frequency. As that frequency approaches the system's own natural frequency the amplitude rises sharply: this is resonance. Damping reduces the height of the resonance peak and broadens it.

DampingBehaviourExample
noneamplitude constant foreveran idealisation only
lightmany oscillations, slowly decayinga swinging pendulum
criticalreturns fastest with no overshootcar suspension, door closers
heavyslow return, no oscillationa pendulum in treacle

What resonance requires, and what damping does to it

  1. Resonance occurs when the driving frequency equals the natural frequency.
  2. At resonance the amplitude is a maximum and energy transfer is most efficient.
  3. More damping gives a lower and broader resonance peak.
  4. Heavy damping also shifts the peak slightly below the natural frequency.
  5. Useful resonance: musical instruments, radio tuning, MRI scanners.
  6. Unwanted resonance: bridges under rhythmic loading, vibrating machinery.
04

Reading the three graphs against each other

Displacement, velocity and acceleration all vary sinusoidally with time, but they peak at different moments — and the relationships between the three graphs are examined more often than the equations themselves.

Velocity is the gradient of the displacement graph, so it is a quarter of a cycle ahead: where displacement is at a maximum its gradient is zero, and where displacement crosses zero its gradient is steepest. Acceleration is the gradient of velocity, putting it another quarter cycle ahead — which makes it exactly half a cycle out of step with displacement.

That half-cycle relationship is simply a = −ω²x drawn out. Whenever displacement is positive the acceleration is negative, so the acceleration graph is the displacement graph turned upside down and scaled by ω².

At this pointDisplacementVelocityAcceleration
equilibrium, moving right0+maximum0
maximum right+x₀0−maximum
equilibrium, moving left0−maximum0
maximum left−x₀0+maximum

Energy has twice the frequency

Kinetic energy is at a maximum every time the object passes through the centre — which happens twice per oscillation, once in each direction. So the energy graphs complete two full cycles for every one cycle of displacement. Sketching an energy-time graph with the same period as the displacement is a common and costly error.

05

Two systems, and what actually sets the period

The syllabus needs two concrete oscillators, and the useful thing about them is what each period formula does not contain.

A mass on a spring has period T = 2π√(m/k). A heavier mass has more inertia and swings more slowly; a stiffer spring pulls harder and swings faster. Notably, gravity does not appear at all — the same spring oscillates at the same rate on the Moon, because gravity only shifts the equilibrium position rather than changing the restoring force about it.

A simple pendulum has period T = 2π√(L/g). Here the mass is absent instead, for the same reason a heavier object does not fall faster: a larger mass has proportionally more weight pulling it back, and the two cancel. Only the length and the local gravitational field strength matter, which is why a pendulum can be used to measure g.

SystemPeriodDepends onDoes NOT depend on
mass on a springT = 2π√(m/k)mass and stiffnessgravity, amplitude
simple pendulumT = 2π√(L/g)length and gmass, amplitude

The pendulum formula assumes a small angle

T = 2π√(L/g) holds only for small oscillations, roughly under 10°. The derivation replaces sin θ with θ, which is accurate only for small angles in radians. At larger amplitudes the motion is still periodic but no longer simple harmonic, and the period grows slightly — so isochronism itself quietly fails once the swing gets wide.

Practice questions

5 questions · 18 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 7 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State the two conditions required for a body to perform simple harmonic motion.
Model answer

The acceleration must be proportional to the displacement from a fixed equilibrium point, and it must be directed towards that point. Together these give a = −ω²x.

Examiner tip. One mark each. Omitting the direction — the minus sign — is the standard way to lose the second mark.

SQ2[2 marks]
State where in the oscillation the speed is greatest and where the acceleration is greatest, giving a reason for each.
Model answer

Speed is greatest at the equilibrium position, because all the energy is kinetic there and the net force is zero. Acceleration is greatest at maximum displacement, because the restoring force is largest there — although the body is momentarily at rest.

Examiner tip. The two maxima are at opposite points, which is the counter-intuitive part being tested.

SQ3[3 marks]
Explain what is meant by resonance, and describe the effect of increasing the damping on the resonance curve.
Model answer

Resonance occurs when the frequency of a driving force equals the natural frequency of the system, producing a maximum amplitude and the most efficient transfer of energy. Increasing the damping makes the peak lower and broader, and shifts it slightly to a lower frequency.

Examiner tip. Three marks: the frequency-matching condition, the maximum amplitude, and both effects of damping on the curve.

Solved numericals

1 · 4 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
A mass on a spring oscillates with amplitude 4.0 cm and period 0.80 s. Calculate the maximum speed and the maximum acceleration.
Full working
  1. ω = 2π/T = 2π/0.80 = 7.854 rad s⁻¹Angular frequency comes first; everything else is built on it.[1]
  2. v_max = ωx₀ = 7.854 × 0.040The amplitude must be converted to metres.[1]
  3. v_max = 0.314 m s⁻¹Occurring at the equilibrium position.[1]
  4. a_max = ω²x₀ = 61.68 × 0.040 = 2.47 m s⁻²Occurring at maximum displacement, where the speed is zero.[1]

v_max = 0.314 m s⁻¹, a_max = 2.47 m s⁻²

Exam questions

1 · 7 marks

Multi-part questions with a full mark scheme.

Q1[7 marks]
A simple pendulum of length 1.2 m oscillates with amplitude 5.0 cm. Take g = 9.81 m s⁻².
(a) Calculate its period.
(b) Calculate the maximum speed of the bob.
(c) The amplitude is doubled. State the effect on the period and on the total energy, justifying each.
(d) Explain what is meant by critical damping and give one application.
Mark scheme
  1. (a) T = 2π√(L/g) = 2π√(1.2/9.81) = 2π√0.12232The standard pendulum formula.[1]
  2. T = 2.20 sClose to 2 s, as expected for a metre-scale pendulum.[1]
  3. (b) ω = 2π/2.20 = 2.856 rad s⁻¹; v_max = ωx₀ = 2.856 × 0.050Converting 5.0 cm to 0.050 m.[1]
  4. v_max = 0.143 m s⁻¹At the lowest point of the swing.[1]
  5. (c) The period is unchanged, because T = 2π√(L/g) contains no amplitude termIsochronism — the property that made pendulum clocks possible.[1]
  6. The total energy is quadrupled, since E ∝ x₀² and the amplitude has doubledThe squared dependence is the point of the part.[1]
  7. (d) Critical damping returns the system to equilibrium in the shortest time without overshooting — used in car suspension or door closers.Definition plus a named application.[1]

(a) 2.20 s; (b) 0.143 m s⁻¹; (c) period unchanged, energy ×4; (d) fastest return without overshoot