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Nuclear Physics

Mass defect, binding energy, fission, fusion and reactors

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01

Mass defect and binding energy

Definition

Binding energy — The energy that would be needed to separate a nucleus completely into its individual nucleons — equivalently, the energy released when it formed.

Weigh a nucleus carefully and it comes out lighter than the protons and neutrons it is made of. Helium-4 is about 0.7% lighter than two protons plus two neutrons weighed separately.

That missing mass is the mass defect, and it is not an error. When the nucleons came together, energy was released, and by E = mc² that released energy came out of the mass. The nucleus is lighter by exactly the amount of energy it gave up.

The same energy is what now holds it together: to pull the nucleus apart you would have to put that energy back. It is therefore called the binding energy.

Because is so enormous, a tiny mass difference corresponds to a huge energy — which is why nuclear processes release millions of times more energy per atom than chemical ones. Burning a carbon atom releases a few electronvolts; fissioning a uranium nucleus releases about 200 million.

Δm = (Z m_p + N m_n) − m_nucleusE_binding = Δm c²1 u = 931.5 MeVthe conversion 1 u = 931.5 MeV saves converting through joules every time
Δm
mass defectkg or u
Z
protons
N
neutrons
c
3.0 × 10⁸m s⁻¹
02

Binding energy per nucleon

Total binding energy is not the useful comparison, because a big nucleus has more of everything. Divide by the number of nucleons and you get binding energy per nucleon — a fair measure of how tightly bound each particle is, and therefore how stable the nucleus is.

Plot it against nucleon number and the curve rises steeply from hydrogen, peaks around iron-56 at about 8.8 MeV per nucleon, then falls slowly towards uranium.

Iron sits at the top because it is the most stable nucleus there is. Everything else is somewhere down one side of that peak, and that single fact governs which nuclear reactions release energy.

Move up the curve and energy is released. For light nuclei that means joining them together — fusion. For heavy nuclei it means splitting them apart — fission. Both routes end nearer iron, and both release the difference.

Drag the marker. To the left of iron, joining nuclei climbs the curve — fusion releases energy. To the right, splitting them climbs it — fission releases energy. Iron itself yields nothing either way, which is why stellar fusion stops there.

Why stars die at iron

A star fuses lighter elements and releases energy each time, climbing the curve. Once its core is iron there is nowhere left to go — fusing iron would absorb energy, not release it. The outward pressure fails, and a massive star collapses and explodes as a supernova.

03

Fission and the chain reaction

In fission, a heavy nucleus such as uranium-235 absorbs a slow neutron, becomes unstable, and splits into two lighter nuclei — plus, crucially, two or three more neutrons.

Those spare neutrons can go on to split further nuclei, which release more neutrons again. That is a chain reaction. Left uncontrolled it grows exponentially, which is a bomb; controlled, it is a power station.

A reactor controls it with three components. Fuel rods hold the uranium. A moderator — usually graphite or water — slows the fast neutrons down, because slow neutrons are far more readily absorbed and are what sustain the reaction. Control rods of boron or cadmium absorb neutrons, and are pushed in or drawn out to hold the reaction exactly steady, at one neutron from each fission going on to cause the next.

The energy appears as kinetic energy of the fragments, which heats a coolant, which raises steam, which drives a turbine. The nuclear part is only the boiler; the rest is an ordinary power station.

The difficulty is the waste. The fragments are themselves radioactive, some with half-lives of thousands of years, and must be stored securely for far longer than any institution has ever lasted.

Worked example 15 marks

In a fission reaction the total mass decreases by 0.215 u. Calculate the energy released in MeV and in joules. Take 1 u = 931.5 MeV and 1 eV = 1.6 × 10⁻¹⁹ J.

  1. Uses E = Δm × 931.5 MeV.The conversion avoids going through kilograms and joules.
  2. E = 0.215 × 931.5.
  3. E = 200 MeV.A typical fission yield — a good check that the arithmetic is right.
  4. Converts: 200 × 10⁶ × 1.6 × 10⁻¹⁹.
  5. E = 3.2 × 10⁻¹¹ J.Tiny per nucleus, but a kilogram of uranium holds about 10²⁴ of them.

200 MeV, or 3.2 × 10⁻¹¹ J

04

Fusion

In fusion, light nuclei join to form a heavier one. In the Sun, hydrogen becomes helium, and about four million tonnes of mass become energy every second.

Fusion releases more energy per kilogram than fission, its fuel is effectively unlimited — hydrogen isotopes from seawater — and its products are not long-lived radioactive waste. On every measure it is the better option.

The obstacle is getting the nuclei close enough. Both are positive and repel fiercely, and the strong nuclear force only takes over at extremely short range. Overcoming that repulsion needs temperatures of millions of kelvin, at which matter is a plasma that no container can touch.

The Sun manages it with gravity, which confines and compresses its core. On Earth the same conditions must be produced with magnetic fields or lasers, and holding a plasma stable long enough to get more energy out than went in has taken seventy years and is not finished.

That is why every power station running today uses fission, and why fusion remains the thing that would change everything if it worked.

FissionFusion
What happensa heavy nucleus splitslight nuclei join
Fueluranium, plutoniumhydrogen isotopes
Conditionsslow neutrons, room temperaturemillions of kelvin
Wastelong-lived radioactive fragmentshelium, essentially harmless
Energy per kglargelarger still
In use today?yes, worldwidenot yet

Key points

  1. A nucleus is lighter than its separate nucleons; that mass defect is its binding energy.
  2. E = Δmc², and 1 u = 931.5 MeV.
  3. Binding energy per nucleon peaks at iron-56 — the most stable nucleus.
  4. Fusion releases energy below iron; fission releases it above.
  5. A reactor needs a moderator to slow neutrons and control rods to absorb them.

Practice questions

6 questions · 25 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Explain what is meant by the mass defect of a nucleus.
Model answer

The difference between the total mass of the separate nucleons and the mass of the assembled nucleus. The nucleus is lighter, because energy was released when it formed.

Examiner tip. Say which way round it is — the nucleus is the lighter one.

SQ2[2 marks]
Explain why binding energy per nucleon, rather than total binding energy, is used to compare nuclei.
Model answer

Total binding energy simply grows with the number of nucleons. Dividing by that number gives a fair measure of how tightly each nucleon is held, and therefore of stability.

Examiner tip. The point is comparability between nuclei of very different sizes.

SQ3[2 marks]
State the purpose of the moderator and of the control rods in a fission reactor.
Model answer

The moderator slows fast neutrons down, because slow neutrons are much more readily absorbed and sustain the chain reaction. The control rods absorb neutrons, and are moved to keep the reaction steady.

Examiner tip. Moderator slows, control rods absorb. Swapping them is the standard error.

Solved numericals

1 · 5 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[5 marks]
A helium-4 nucleus has a mass defect of 0.0304 u. Calculate its total binding energy in MeV and the binding energy per nucleon. Take 1 u = 931.5 MeV.
Full working
  1. Uses E = Δm × 931.5[1]
  2. E = 0.0304 × 931.5[1]
  3. E = 28.3 MeV[1]
  4. Divides by the 4 nucleons[1]
  5. = 7.1 MeV per nucleonhigh for such a light nucleus, which is why helium is so stable[1]

28.3 MeV total, 7.1 MeV per nucleon

Examiner tip. Helium-4 is unusually tightly bound for its size — it sits well above the smooth curve, and that is why alpha particles exist as a unit.

Long questions

1 · 8 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[8 marks]
The graph of binding energy per nucleon against nucleon number rises to a peak near iron-56 and then falls.
  1. Explain what the peak tells you about iron-56. [2]
  2. Explain, using the graph, why fusion releases energy for light nuclei and fission for heavy ones. [4]
  3. Explain why fusion in a star stops once the core is iron. [2]
Mark scheme
  1. Iron-56 has the greatest binding energy per nucleon[1]
  2. So it is the most stable nucleus[1]
  3. Joining light nuclei produces a nucleus higher on the curve[1]
  4. The products are more tightly bound, so energy is released[1]
  5. Splitting a heavy nucleus produces fragments higher on the curve[1]
  6. Again the products are more tightly bound, so energy is released[1]
  7. Fusing iron would produce nuclei lower on the curve, which absorbs energy rather than releasing it[1]
  8. With no energy released, the outward pressure supporting the star fails and the core collapses[1]

iron is most stable; both processes move products up the curve; fusing iron would absorb energy

Examiner tip. The phrase to use throughout is "moves up the curve". Both processes do it, from opposite sides.

Exam questions

1 · 6 marks

Multi-part questions with a full mark scheme.

Q1[6 marks]
Compare nuclear fission and nuclear fusion as sources of electrical power.
  1. State one advantage of fusion over fission. [2]
  2. Explain the main difficulty in building a fusion reactor. [3]
  3. State which process is used in power stations today. [1]
Mark scheme
  1. Fusion produces no long-lived radioactive waste — the product is helium[1]
  2. And its fuel, hydrogen isotopes, is effectively unlimitedeither point, developed[1]
  3. Both nuclei are positively charged and repel strongly[1]
  4. They must be brought close enough for the strong nuclear force to act, needing temperatures of millions of kelvin[1]
  5. At those temperatures the plasma cannot touch any container, so it must be confined magnetically, and holding it stable long enough to gain net energy is unsolved[1]
  6. Fission[1]

fusion: no long-lived waste, unlimited fuel; difficulty is containment at millions of kelvin; fission is used today

Examiner tip. Be specific about the difficulty. "It is hard" earns nothing; electrostatic repulsion, the temperature needed, and confinement earn all three.