PhysicsCore24 min read

Mechanics

Motion, forces and energy

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01

Forces change motion, they do not maintain it

Definition

Resultant force — The single force that has the same effect as all the forces acting on a body combined.

The hardest idea in mechanics is also the first one: a moving object does not need a force to keep moving. Everyday experience suggests otherwise, because everything we push eventually stops — but it stops because of friction, not because the push ran out.

Newton's first law states that an object stays at rest, or continues at constant velocity in a straight line, unless a resultant force acts on it. Constant velocity and rest are the same case as far as the physics is concerned: both mean no resultant force.

So a force is not what keeps a body moving. A force is what changes how it moves — speeding it up, slowing it down, or bending its path. A spacecraft coasting between planets has no engine running and does not slow down at all.

Constant velocity means balanced forces

A car travelling at a steady 80 km/h has zero resultant force on it. The engine's driving force exactly balances air resistance and friction. Students often write that the driving force must be bigger — it is not, or the car would be accelerating.

02

Newton's second law

When there is a resultant force, the body accelerates. Newton's second law says the acceleration is proportional to the resultant force and inversely proportional to the mass, which gives the single most used equation in mechanics.

Two things about it are worth stating carefully. The F is the resultant force, not any one of the individual forces — you must combine them first. And the acceleration is always in the same direction as that resultant force.

The inverse relationship with mass is the part that feels intuitive: push a shopping trolley and an identical push produces far less acceleration when it is full. Mass is the measure of that resistance to being accelerated, which is why it is also called inertia.

F = m aa = F / mF is the RESULTANT force, in newtons; one newton accelerates one kilogram at one metre per second squared
F
resultant forceN
m
masskg
a
accelerationm s⁻²
Worked example 15 marks

A 1200 kg car has a driving force of 3600 N. Air resistance and friction together total 1200 N. Calculate its acceleration, and then the resistive force when it travels at constant speed.

  1. Resultant force = 3600 − 1200 = 2400 N.Combine the forces before using F = ma — this is the step most often skipped.
  2. a = F/m = 2400 / 1200.
  3. a = 2.0 m s⁻².
  4. At constant speed the acceleration is zero, so the resultant force is zero.Newton's first law.
  5. Therefore resistance = 3600 N, equal and opposite to the driving force.Not zero — the forces balance, they do not vanish.

a = 2.0 m s⁻²; resistance = 3600 N at constant speed

03

Newton's third law, and the pair that never cancels

For every force there is an equal and opposite force. If you push a wall with 50 N, the wall pushes you back with 50 N. The two forces are always the same size, always opposite in direction, and always the same type of force.

The point that decides most exam questions is this: the two forces of a third-law pair act on different bodies. They can therefore never cancel each other out, because cancelling only happens between forces acting on the same object.

A book resting on a table makes the distinction clear. The book's weight (Earth pulling book) pairs with the book pulling the Earth up — not with the table's push on the book. The table's push happens to be equal and opposite to the weight, but that is a balance, not a third-law pair.

Balanced forcesThird-law pair
Act onthe same bodytwo different bodies
Type of forcemay be different typesalways the same type
Can they cancel?yes — that is the pointnever
Exampleweight and table push on a bookEarth pulls book, book pulls Earth
04

Friction, drag and terminal velocity

Friction opposes motion between surfaces in contact, and drag does the same job in a fluid. Both convert kinetic energy into internal energy, which is why brakes get hot.

Drag differs from ordinary friction in one crucial way: it increases with speed. That single fact produces terminal velocity, which is one of the most commonly examined sequences in the whole subject.

A skydiver leaving an aircraft has weight acting down and almost no drag, so the resultant force is large and the acceleration is close to g. As speed builds, drag grows. The resultant force shrinks, so the acceleration falls — the diver is still speeding up, but less quickly. Eventually drag equals weight, the resultant force is zero, and the speed stops changing. That constant speed is the terminal velocity.

Opening a parachute increases the drag sharply. Drag now exceeds weight, so the resultant force acts upward and the diver decelerates — slowing down until drag has fallen back to equal weight, giving a new, much lower terminal velocity.

The amber arrow stays the same length for the whole flight — with no horizontal force there is no horizontal acceleration. The cyan arrow shrinks, reverses and grows, because gravity acts on the vertical motion alone.

Key points

  1. Drag increases with speed; friction between solid surfaces does not.
  2. Terminal velocity is reached when drag equals weight, giving zero resultant force.
  3. At terminal velocity the object is still moving fast — it has simply stopped accelerating.
  4. Opening a parachute makes drag exceed weight, so the diver slows down.
  5. The new terminal velocity is lower, but it is still reached the same way.
05

Circular motion

An object moving in a circle at constant speed is still accelerating, and this catches almost everyone out. Velocity is a vector, so it has direction as well as size. Going round a bend changes the direction continuously, so the velocity is changing continuously, and a changing velocity is an acceleration.

That acceleration needs a resultant force, directed towards the centre of the circle. It is called the centripetal force, and it is not a new kind of force — it is whatever real force happens to be doing the job. For a car on a bend it is friction between tyres and road. For a planet it is gravity. For a bucket swung on a rope it is tension.

The force needed grows with speed and with mass, and falls as the radius increases. This is why a car takes a tight bend more slowly than a gentle one: the friction available is fixed, so the speed must come down.

There is no outward force

The feeling of being thrown outwards in a turning car is your body continuing in a straight line while the car turns beneath you — Newton's first law, not a force. Writing "centrifugal force" in an exam answer loses marks. The only force is inward.

Practice questions

5 questions · 14 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State Newton's third law and give the two conditions an action–reaction pair must satisfy.
Model answer

For every action there is an equal and opposite reaction. The two forces are of the same type and act on different bodies.

Examiner tip. The two conditions separate a full answer from a half one, and they are what the follow-up question always probes.

SQ2[2 marks]
Why does a passenger lurch forward when a bus brakes suddenly?
Model answer

By Newton's first law the passenger continues moving at the same velocity because no resultant force acts on them; the bus decelerates beneath them, so they move forward relative to it.

Examiner tip. Name the law and describe the relative motion. "Because of inertia" alone scores one.

SQ3[2 marks]
Define momentum and state its SI unit.
Model answer

The product of mass and velocity, p = mv. A vector quantity. SI unit: kg m s⁻¹.

Examiner tip. Mentioning that it is a vector is often the second mark, and it costs four words.

Solved numericals

2 · 8 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
A trolley of mass 2.0 kg moving at 3.0 m s⁻¹ collides with a stationary trolley of mass 4.0 kg. They stick together. Calculate their common velocity after the collision.

Given. m₁ = 2.0 kg, u₁ = 3.0 m s⁻¹, m₂ = 4.0 kg, u₂ = 0

Full working
  1. States conservation of momentum: total before = total after[1]
  2. Before: p = 2.0 × 3.0 + 4.0 × 0 = 6.0 kg m s⁻¹[1]
  3. After: combined mass = 6.0 kg, so 6.0 = 6.0 × vthey stick together, so they share one velocity[1]
  4. v = 1.0 m s⁻¹ in the original directiondirection expected for full marks[1]

1.0 m s⁻¹ in the direction of the original motion

N2[4 marks]
A force of 15 N acts on a 3.0 kg block resting on a surface. Friction opposing the motion is 6.0 N. Calculate the acceleration of the block.

Given. F_applied = 15 N, f = 6.0 N, m = 3.0 kg

Full working
  1. Resultant force = 15 − 6.0 = 9.0 Nfriction opposes, so it subtracts[1]
  2. Uses F = ma[1]
  3. a = F/m = 9.0 / 3.0[1]
  4. a = 3.0 m s⁻²unit required[1]

3.0 m s⁻²

Examiner tip. Always find the resultant force before using F = ma. Substituting the applied force alone gives 5.0 m s⁻² and scores one of four.